Let us assume the first number is a and common difference is d.
According to question,
4th term of A.P = 37
a + ( n - 1 ) x d = 37
Put the value of a , n and d, we will get,
a + (4 - 1 ) x d = 37
a + 3d = 37..................(1)
sixth term is 12 more than the fourth term,
6th term = 12 + 4th term
a + ( n - 1 ) x d = 12 + 37
a + ( 6- 1 ) x d = 39
a + 5d = 39................(2)
subtract the equation (1) from (2)
a + 5d - a - 3d = 39 - 37
5d - 3d= 2
2d = 2
d = 1
Put the value of d in equation (1), we will get
a + 3 x 1 = 37
a = 37 - 3
a = 34
Second term = a + (n - 1) x d = 34 + (2 - 1) x 1 = 34 + 1 = 35
Six term = a + (n - 1) x d = 34 + (6 - 1) x 1 = 34 + 5 = 39
Sum of Second and Six term = 35 + 39 = 74
Sum of Second and Six term = 74
Answer is 74.
Area of equilateral triangle = ?3/4 a2 = 4?3.
? a2 = 16
? a = 4 cm
Here, n = 2, m =10, T1 = 6 yr, T2 = ?
? T2 = [(m - 1) / (n - 1)] x T1
= [(10 - 1)/(2 - 1)] x 6
= 54 yr
Given, SI1 - SI2 = 110,
T1 = 2 Yr,
T2 = 1 yr, R1 = 8%, R2 = 5%
According to the question,
[(P x 8 x 2)/100] - [(P x 5 x 1)/100] = 110
? 11P/100 = 110
? P = ? 1000
Let the positive number be N.
According to the question,
N + 10 = 200 / N
? N2 + 10N = 200
? N2 +10N - 200 =0
? (N - 10)(N + 20) = 0
? N = 10 & N= -20
But N not equal to -20 since N is a positive number
So, the required number is 10
Let the sum be p
Then, for R = 5%
SI = (4p - p) = 3p
? 3p = (P x 5 x T)/100 = PT/20
? T = 60 yr
Again, for another rate (R)
SI = (8P - P) = 7P
? 7P = (P x R x 60)/100
? R = (7 x 100)/60 = 35/3%
= 112/3 %
Here, P = ? 65800, R = 14% T = 4 yr
Hence, SI = (65800 x 14 x 4) / 100 =? 36848
? Required amount = P + SI
= 65800 + 36848
= ? 102648
Cost of 5 pens + 8 pencils = ?31
On multiplying by 3
15 pens + 24 pencils = 3 x 31 =
?15 pens + 24 pencils = 93
Given that, a = 8 cm, b = 10 cm and c = 12 cm
We know, that
s = (a + b + c)/2
= (8 + 10 + 12)/2
= 30/2 = 15 cm
? (s - a) = (15 - 8) = 7 cm
(s - b) = (15 - 10) = 5 cm
(s - c) = (15 - 12) = 3 cm
? Area = ?s(s - a) (s - b) (s - c)
= ?15 x 7 x 5 x 3
= ?1575
= ?25 x 63
= 5?63 cm
Let each sum be ? P then,
(P x 10 x 5)/100 - (P x 10 x 4)/100 = 220
? P/10 = 220
? P = 2200
Hence, each sum is ? 2200.
Let the number be N.
According to the question,
N - (N x 3/4) =163
? N/4 =163
? N=652
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