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  • Question
  • The Fourth term of an Arithmetic Progression is 37 and the Sixth term is 12 more than the Fourth term. What is the sum of the Second and Eight terms?


  • Options
  • A. 54
  • B. 64
  • C. 74
  • D. 84

  • Correct Answer
  • 74 

    Explanation

    Let us assume the first number is a and common difference is d.
    According to question,
    4th term of A.P = 37
    a + ( n - 1 ) x d = 37
    Put the value of a , n and d, we will get,
    a + (4 - 1 ) x d = 37
    a + 3d = 37..................(1)
    sixth term is 12 more than the fourth term,
    6th term = 12 + 4th term
    a + ( n - 1 ) x d = 12 + 37
    a + ( 6- 1 ) x d = 39
    a + 5d = 39................(2)
    subtract the equation (1) from (2)
    a + 5d - a - 3d = 39 - 37
    5d - 3d= 2
    2d = 2
    d = 1
    Put the value of d in equation (1), we will get
    a + 3 x 1 = 37
    a = 37 - 3
    a = 34

    Second term = a + (n - 1) x d = 34 + (2 - 1) x 1 = 34 + 1 = 35
    Six term = a + (n - 1) x d = 34 + (6 - 1) x 1 = 34 + 5 = 39
    Sum of Second and Six term = 35 + 39 = 74
    Sum of Second and Six term = 74
    Answer is 74.


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    • A. 6
    • B. 8
    • C. 9.5
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    • 2. 
      The value of 47 / 10000 is?

    • Options
    • A. .0047
    • B. .0470
    • C. .00047
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    • 3. If 4x = 18y, then the value of ( x/y - 1) is

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    • 4. 
      If the price of 23 toys is Rs. 276, then what will the price (Rs.) of 12 toys?

    • Options
    • A. 144
    • B. 158
    • C. 159
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    • 5. 
      .02 =(......?.....)%

    • Options
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    • 6. 
      If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it?

    • Options
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    • 7. 
      2?63 / 11 =233

    • Options
    • A. 4
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    • 8. 
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    • Options
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