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  • Question
  • The Fourth term of an Arithmetic Progression is 37 and the Sixth term is 12 more than the Fourth term. What is the sum of the Second and Eight terms?


  • Options
  • A. 54
  • B. 64
  • C. 74
  • D. 84

  • Correct Answer
  • 74 

    Explanation

    Let us assume the first number is a and common difference is d.
    According to question,
    4th term of A.P = 37
    a + ( n - 1 ) x d = 37
    Put the value of a , n and d, we will get,
    a + (4 - 1 ) x d = 37
    a + 3d = 37..................(1)
    sixth term is 12 more than the fourth term,
    6th term = 12 + 4th term
    a + ( n - 1 ) x d = 12 + 37
    a + ( 6- 1 ) x d = 39
    a + 5d = 39................(2)
    subtract the equation (1) from (2)
    a + 5d - a - 3d = 39 - 37
    5d - 3d= 2
    2d = 2
    d = 1
    Put the value of d in equation (1), we will get
    a + 3 x 1 = 37
    a = 37 - 3
    a = 34

    Second term = a + (n - 1) x d = 34 + (2 - 1) x 1 = 34 + 1 = 35
    Six term = a + (n - 1) x d = 34 + (6 - 1) x 1 = 34 + 5 = 39
    Sum of Second and Six term = 35 + 39 = 74
    Sum of Second and Six term = 74
    Answer is 74.


  • More questions

    • 1. 
      The simplified form of log(75/16) -2 log(5/9) +log(32/343) is?

    • Options
    • A. log 2
    • B. 2 log 2
    • C. log 3
    • D. log 5
    • Discuss
    • 2. 
      If log 2 = 0.3010 then log 5 equals to?

    • Options
    • A. 0.3010
    • B. 0.6990
    • C. 0.7525
    • D. Given log 2, it is not possible to calculate log 5
    • Discuss
    • 3. 
      If log 102 =0.3010 and log 107 = 0.8451, then the value of log 10 2.8 is?

    • Options
    • A. 0.4471
    • B. 1.4471
    • C. 2.4471
    • D. 14.471
    • Discuss
    • 4. 
      A merchant has announced 25% rebate on prices of ready made garments at the time of sale. If a purchaser needs to have a rebate of ? 400, then how many shirts, each costing ? 320, should he purchase?

    • Options
    • A. 10
    • B. 7
    • C. 6
    • D. 5
    • Discuss
    • 5. 
      In the year 2011, Shantanu gets a total of 3832.5 Rupee as his pocket allowence. Find his pocket allowence per day.

    • Options
    • A. 9.5 Rupees
    • B. 10.5 Rupees
    • C. 12.5 Rupees
    • D. 11.5 Rupees
    • Discuss
    • 6. 
      26.003 - 154 .001 ÷ 6.995 =?

    • Options
    • A. 4
    • B. 18
    • C. 9
    • D. 10
    • Discuss
    • 7. 
      Given that log 10 2 = 0.3010, then log 2 10 is equal to?

    • Options
    • A. 0.3010
    • B. 0.6990
    • C. 1000 / 301
    • D. 699 / 301
    • Discuss
    • 8. 
      The sum of 4 consecutive even number is 284. What would be the smallest number?

    • Options
    • A. 72
    • B. 74
    • C. 68
    • D. 66
    • Discuss
    • 9. 
      A man travels 35 km partly at 4 km/hr and at 5 km/hr. If he covers former distance at 5 km/hr and later distance at 4 km/hr, he could cover 2 km more in the same time. The time taken to cover the whole distance at original rate is

    • Options
    • A. 9 hours
    • B. 7 hours
    • C. 4.5 hours
    • D. 8 hours
    • Discuss
    • 10. The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker's discount is:

    • Options
    • A. Rs. 960
    • B. Rs. 840
    • C. Rs. 1020
    • D. Rs. 760
    • Discuss


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