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- Question
- The average weight of 4 men, A, B, C and D is 67 kg. The 5th man E is included and the average weight decreses by 2 kg. A is replaced by F. The weight of F is 4 kg more then E . Average weight decreases because of the replacement of A and now the average weight is 64 kg. Find the weight of A.
Options- A. 78 kg
- B. 66 kg
- C. 75 kg
- D. 58 kg
- Correct Answer
- 66 kg
ExplanationSum of the weight of A, B, C and D = 67 x 4 = 268 kg
and average weight of A, B , C , D and E = 67 - 2 = 65kg
? Sum of the weight of A, B, C, D and E = 65 x 5 = 325 kg
? Weight of E = 325 - 268 = 57 kg
? Weight of F = 57 + 4 = 61 kg
Now, average weight of F, B, C, D and E = 64 kg
? Sum of the weight of F, B, C, D and E = 64 x 5 = 320 Kg
? Sum of the weights of B, C and D = 320 - 57 - 61 = 202 kg
? Weight of A = 268 - 202 = 66 kg - 1. If a : b = 2 : 3 and 2 : a =1 : 2, then the value of 'b' is?
Options- A. 4
- B. 6
- C. 1 / 3
- D. 3 / 2 Discuss
- 2. 0.6 of a number equals 0.09 of another number. The ratio of the number is?
Options- A. 2 : 3
- B. 1 : 15
- C. 20 : 3
- D. 3 : 20 Discuss
- 3. If a/3 = b/8, then ( a + 3 ) : ( b + 8 ) is equal to?
Options- A. 3 : 8
- B. 8 : 3
- C. 5 : 8
- D. 3 : 5 Discuss
- 4. 4, 19, 49,?, 229
Options- A. 75
- B. 109
- C. 65
- D. 169 Discuss
- 5. 777777 / 11 =?
Options- A. 7077
- B. 70707
- C. 7707
- D. 7007 Discuss
- 6. Find the cardinal number of the following set {x: x is a natural number ? 30 and is divisible by 7 or 11}
Options- A. 4
- B. 8
- C. 6
- D. 2 Discuss
- 7. SBI lent ? 1331 lakh to the TATA group at compound interest and got ?1728 lakh after 3 yr. What is the rate of interest charged, if compounded annually?
Options- A. 11%
- B. 9.09%
- C. 12%
- D. 8.33% Discuss
- 8. The sum of two numbers is 10. Their product is 20. Find the sum of the reciprocals of the two numbers.
Options- A. 1
- B. 3/5
- C. 1/2
- D. 11//6 Discuss
- 9. 5 men and 6 women can earn ? 2160 in 4 days. 8 men and 10 women can earn ? 4400 in 5 days. In how many days can 4 men and 9 women earn ? 1800?
Options- A. 3
- B. 4
- C. 5
- D. 6 Discuss
- 10. A train 110 metres long travels at 60 km/hr. How long does it take to cross a telegraph post?
Options- A. 5 sec.
- B. 5.6 sec
- C. 6.6 sec
- D. 6.8 sec Discuss
More questions
Correct Answer: 6
Explanation:
? a / b = 2/3 and 2 / a = 1/2
? a/b x 2/a = 2/3 x 1/2
? 2/b = 1/3
? b = 6
Correct Answer: 3 : 20
Explanation:
0.6 x a = 0.09 x b
? a/b = 0.09 / 0.06 = 9 / 60 = 3 / 20 = 3 : 20
Correct Answer: 3 : 8
Explanation:
Let a/3 = b/8 = K
Then, a = 3K, b = 8K
? (a + 3) / (b + 8) = (3K + 3) / (8K + 8)
= [3( K + 1)] / [8(K+1)] = 3/8
? ( a + 3 ) : (b + 8) = 3 : 8
Correct Answer: 109
Explanation:
Series pattern +15, + 30, +60, +120
? Missing term = 49 + 60 = 109
Correct Answer: 70707
Explanation:
777777 / 11 = 70707.
Correct Answer: 6
Explanation:
NA
Correct Answer: 9.09%
Explanation:
According to the question,
1728 = 1331(1 + R/100)3
1728/1331 = (1 + R/100)3
? (12/11)3 = (1 + R/100)3
? 1 + R/100 = 12/11
? R/100 = (12/11) - 1 = 1/11
? R = 100/11= 9.09%
Correct Answer: 1/2
Explanation:
Here, M + N = 10 and MN = 20
According to the question,
(1/M) + (1/N) = (M + N) / MN = 10/20 = 1/2
Correct Answer: 3
Explanation:
Correct Answer: 6.6 sec
Explanation:
Time = distance / speed
=110 / {60 x 18/5} = 6.6 sec.
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