Let average of the remaining student be y.
Then from questions ( 5 x 10 ) + ( 5 x 14) + 20y = 30 x 12
? 50 + 70 + 20y = 360
? 20y = 360 ? 120
? 20y = 240
? y = 12.
We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).
Required number of ways =
= = 209.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.