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- Question
- If a, b, c, d, e are five consecutive odd number , their average is?
Options- A. 5 (a + 4)
- B. abcd/5
- C. 5 (a + b + c + d + e)
- D. None of these
- Correct Answer
- None of these
ExplanationSince a, b, c, d, e are 5 consecutive numbers so
b = a + 2.
c = a + 4.
d = a + 6.
e = a + 8.
Average = (a + b + c + d + e)/ 5
= [a + (a + 2 ) + (a +4 ) + (a+6 )+ (a+8)] / 5
= (5a+20) / 5
= a + 4 - 1. A man spends average of ? 1694. 70 per month for the first 7 month and ? 1810.50 per month for the next 5 months. His monthly salary if he saves ? 3084.60. during the whole year is?
Options- A. ? 2400
- B. ? 3000
- C. ? 1000
- D. ? 2000 Discuss
- 2. In the afternoon, a student read 100 pages at the rate of 60 pages/h. In the evening, when she was tired, she read 100 more pages at the rate of 40 pages/h . What was her average rate of reading in pages per hour?
Options- A. 48
- B. 50
- C. 60
- D. 70 Discuss
- 3. Average weight of three boys P, T and R is 54 1/ 3 kg, while the average weight of three boys T, F and G is 53 kg. What is the average weight of P, T, R, F and G?
Options- A. 53.8 kg
- B. 52.4 kg
- C. 53.4 kg
- D. Cannot be determined Discuss
- 4. The average runs scored by a cricketer is 42 innings, is 30. The difference between his maximum and minimum scores in an inning is 100. If these two innings are not taken into consideration, then the average score of remaining 40 inning is 28. Calculate the maximum runs scored by him in an innings?
Options- A. 125
- B. 120
- C. 110
- D. 100 Discuss
- 5. A cricketer whose bowling average is 12.4 runs per wicket, takes 5 wickets for 26 runs and there by decreases his average by 0.4. Find out the number of wickets taken by him till the last match?
Options- A. 75
- B. 81
- C. 85
- D. 79 Discuss
- 6. A has double the money of B and B has 50% more money then C. If average money of all the three persons is ? 12000, how money does A have?
Options- A. ? 211000/11
- B. ? 315000/11
- C. ? 216000/11
- D. ? 316000/11 Discuss
- 7. The average weight of the students in four sections A, B, C and D is 60 kg. The average weight of the students of A, B, C and D individually are 45 kg, 50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section A and B together is 48 kg and that of B and C together is 60 kg. What is the ratio of the number of the students in sections A and D?
Options- A. 12 : 7
- B. 4 : 3
- C. 3 : 2
- D. 8 : 5 Discuss
- 8. 125.009 + 69.999 + 104.989 =?
Options- A. 420
- B. 300
- C. 285
- D. 415 Discuss
- 9. 503 x 201=?
Options- A. 101100
- B. 1000000
- C. 110000
- D. 100003 Discuss
- 10. 2 3/ 5 x 15/26 x 283.75 =?
Options- A. 440
- B. 435
- C. 410
- D. 425 Discuss
More questions
Correct Answer: ? 2000
Explanation:
Let the monthly salary of a man = ? N
? The annual salary = ? 12N
According to the question,
Annually spends of a man = 7 x 1694.70 + 5 x 1810.50
= ? 20915.40
? His monthly spends = 20915.40/12 = ? 1742.95
And monthly saving = 3084.60/12 = ? 257.05
? His monthly salary
= 1742.95 + 257.05
= ? 2000
Correct Answer: 48
Explanation:
Required average rate of reading
= 2AB / (A + B) = 2 x 60 x 40 / (60 + 40)
= (2 x 60 x 40)/100 = 48 page/h
Correct Answer: Cannot be determined
Explanation:
According to the question
(P + T + R) / 3 = 541/3
? P + T + R = (163/3) x 3
? P + T + R = 163 ............(i)
Also (T + F + G)/3 = 53
? T + G + F = 159 ..........(ii)
Clearly, from the two Eqs. (i) and (ii), the problem cannot be solved.
Correct Answer: 120
Explanation:
Let the minimum score = x
? Maximum score = x + 100
? x + (x + 100) = 30 x 42 - 40 x 28
? 2x + 100 = 1260 - 1120 = 140
? 2x = 140 - 100 = 40
? x = 20
Hence, the maximum score = x + 100
= 20 + 100 = 120
Correct Answer: 85
Explanation:
Let x be the number of wickets taken till the last match
According to the question,
(12.4 x + 26) = 12(x + 5)
? 12.4 x + 26 = 12x + 60
? 0.4 x = 34
? x = 34/0.4 = 85
Correct Answer: ? 216000/11
Explanation:
Let money of C be ? N.
According to the question
Total money of B = N + N x 50%
= N + 50N/100 = 3N/2
Total money of A = 2 x 3N/2 = 3N
Average money of three persons = 12000
? Total money of three = 12000 x 3
? 3N + (3N/2) + N = 12000 x 3
? (6N + 3N + 2N)/2 = 36000
? N = (36000 x 2)/11 = 72000/11
Now, money of A = 3N = (3 x 72000)/11
= ? 216000/11
Correct Answer: 4 : 3
Explanation:
Let number of students in the sections
A, B, C and D be a, b, c and d respectively.
Then, total weight of students of sections A = 45a
Total weight of students of section B = 50b
Total weight of students of section C = 72c
Total weight of students of section D = 80d
According to the question,
Average weight of students of sections of A and B = 48 kg
? (45a + 50b)/(a + b) = 48
? 45a +50b = 48a + 48b
? 3a = 2b
? 15a = 10b
And average weight of students of sections B and C = 60 kg
? 50b + 72c = 60(b + c)
? 10b = 12c
Now, average weight of students of A, B, C and D = 60 kg
? 45a + 50b + 72c + 80d = 60(a + b + c + d)
? 15a + 10b - 12c - 20d = 0
? 15a = 20d
? a : d = 4 : 3
Correct Answer: 300
Explanation:
125.009 + 69.999 + 104.989 = ?
Lets assume, each value is approximated to nearest whole number
? ? ? 125 + 70 + 105
? ? ? 300
Correct Answer: 101100
Explanation:
530 x 201 = 101103 ? 101100
Correct Answer: 425
Explanation:
? = 23/5 x 15/26 x 283.75
? 13/5 x 15/16 x 284 = 426 ? 425
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