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Home ‣ Aptitude ‣ Problems on H.C.F and L.C.M Comments
- Question
- Find the HCF of 132, 204 and 228.
Options- A. 12
- B. 18
- C. 6
- D. 21
- Correct Answer
- 12
Explanation132 = 2 x 2 x 3 x 11
240 = 2 x 2 x 2 x 2 x 3 x 5
228 = 2 x 2 x 3 x 19
Hence, HCF of 132, 204 and 228 = 2 x 2 x 3 = 12 - 1. Consider the number between 300 and 400 which when divided by 12, 18 and 36 leaves 4 as remainder in each case. what is the sum of the number?
Options- A. 840
- B. 692
- C. 324
- D. 1024 Discuss
- 2. What is the greatest number which divides 390, 480 and 620 so as to leave the same remainder in each case?
Options- A. 15
- B. 10
- C. 20
- D. 19 Discuss
- 3. What is the greatest number that divides 263, 935 and 1383 leaving a remainder of 7 in each case?
Options- A. 30
- B. 31
- C. 32
- D. 35 Discuss
- 4. What are the values of c when the HCF of x 3 + c x 2 - x + 2c and x 2 + cx - 2 over the rational is a linear polynomial?
Options- A. +1
- B. +2
- C. +1
- D. +4 Discuss
- 5. The LCM and HCF of two number are 240 and 16, respectively,If the two numbers are in the ratio 3 : 5, the numbers are?
Options- A. 24, 40
- B. 21, 35
- C. 36, 60
- D. 48, 80 Discuss
- 6. Find the HCF of 4/5 and 7/15?
Options- A. 1/13
- B. 1/5
- C. 1/15
- D. 1/25 Discuss
- 7. Find the HCF of 1/2, 3/4, and 4/5?
Options- A. 1/20
- B. 1/40
- C. 20
- D. 15 Discuss
- 8. Product of two coprime numbers is 117. Then, their LCM is
Options- A. 9
- B. 13
- C. 39
- D. 117 Discuss
- 9. The LCM of two numbers is 2376 while their HCF is 33. If one of the number is 297, then the other number is
Options- A. 216
- B. 264
- C. 642
- D. 792 Discuss
- 10. The HCF and LCM of two numbers are 13 and 1989, respectively. If one of the numbers is 117, then determine the other
Options- A. 121
- B. 131
- C. 221
- D. 231 Discuss
Problems on H.C.F and L.C.M
Search Results
Correct Answer: 692
Explanation:
LCM of (12,18, 36) = 36
? A number greater than 300 on dividing by 36 leaves a remainder 4 = (36 x 9) + 4 = 328
Next numbe r = 328 + 36 = 364
? Sum of number = 328 + 364 = 692
Correct Answer: 10
Explanation:
The HCF of [(480 - 390), (620 - 480), (620 - 390)]
= HCF of 90, 140, 230 = 10
Correct Answer: 32
Explanation:
The required greatest number is the HCF of (263 - 7, 935 - 7, 1383 - 7)
i.e., HCF of 256, 928 and 1376 = 32
Correct Answer: +1
Explanation:
Find HCF of x3 +c x2 -x + 2c and x2 + cx - 2 by long division method and get remainder
? Remainder = 2c - 2/c
Since,remainder should be zero
? 2c2 - 2 = 0
? 2(c2 -1) = 0 ? c= ± 1
Correct Answer: 48, 80
Explanation:
Suppose two numbers are 3N and 5N.
Then, 3N x 5N = HCF x LCM
? 15N2 = 16 x 240
? N2 = 256
? N = 16
So, the number are 3N = 3 x 16 = 48 and 5N = 5 x 16 = 80.
Correct Answer: 1/15
Explanation:
We know that,
HCF of fractions = (HCF of numerators) / (LCM of denominators)
? Required HCF = (HCF of 4 and 7) / (LCM of 5 and 15)
=1/15
Correct Answer: 1/20
Explanation:
Required HCF = (HCF of numerators) / (LCM of denominators)
= (HCF of 1, 3 and 4) / (LCM of 2, 4, and 5)
= 1/20
Correct Answer: 117
Explanation:
LCM of two coprimes is equal to their product.
Correct Answer: 264
Explanation:
Given, LCM of two number = 2376
HCF of two number = 33
One of the number = 297
? (HCF of two numbers) x (LCM of two numbers) = (First number) x (Second number)
? Second number = (33 x 2376)/297
= 264
Correct Answer: 221
Explanation:
Given,
LCM = 1989, HCF = 13
1st number = 117 and
2nd number = ?
According to the formula,
Product of LCM and HCF = Product of two numbers
? 1989 x 13 = 117 x ?
? = (1989 x 13)/117
? = 221
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