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Home ‣ Aptitude ‣ Problems on H.C.F and L.C.M Comments
- Question
- The H.C.F of two number is 16 and their L.CM is 160. If one of the numbers is 32, then the other number is?
Options- A. 48
- B. 80
- C. 96
- D. 112
- Correct Answer
- 80
ExplanationProduct of two numbers = LCM of two numbers x HCF of two numbers.
? N x 32 = 160 x 16
? N = 80 - 1. The product of two-digit numbers is 2160 and their G.C.M is 12. The numbers are?
Options- A. 72, 30
- B. 36, 60
- C. 96, 25
- D. None of these Discuss
- 2. The sum of two number is 216 and their H.C.F is 27. The numbers are?
Options- A. 54, 162
- B. 108, 108
- C. 27, 189
- D. None of these Discuss
- 3. The greatest possible length which can be used to measure exactly the lengths 7m, 3m 85cm, 12m 95 cm, is?
Options- A. 15 cm
- B. 25 cm
- C. 35 cm
- D. 42 cm Discuss
- 4. An inspector of schools wishes to distribute 84 balls and 180 bats equally among a number of boys. Find the greatest number receiving the gift in this ways?
Options- A. 14
- B. 15
- C. 16
- D. 12 Discuss
- 5. What least number must be subtracted from 1936, so that the remainder when divided by 9, 10, 15 will leave in each case the same remainder 7?
Options- A. 46
- B. 53
- C. 39
- D. 44 Discuss
- 6. The product of two numbers is 1600 and their H.C.F is 5. The L.C.M. of the numbers is?
Options- A. 320
- B. 1605
- C. 1595
- D. 8000 Discuss
- 7. About the number of pairs which have 16 as their H.C.F and 136 as their L.C.M. We can definitely say that?
Options- A. Only one such pair exists
- B. Only two such pair exists
- C. Many such pairs exists
- D. No such pair exists Discuss
- 8. The least number, which when divided by 16, 18 and 21 leaves the remainder 3, 5 and 8 respectively, is?
Options- A. 893
- B. 992
- C. 995
- D. 1024 Discuss
- 9. The greatest number of four digits which is divisible by each one of the numbers 12, 18 21 and 28 is?
Options- A. 9848
- B. 9864
- C. 9828
- D. 9636 Discuss
- 10. The least number which when divided by 15, 27, 35 and 42, leaves in each case a remainder 7 is?
Options- A. 1883
- B. 1897
- C. 1987
- D. 2007 Discuss
Problems on H.C.F and L.C.M
Search Results
Correct Answer: 36, 60
Explanation:
Let the number be 12a and 12b
Then 12a x 12b = 2160
or ab = 15
? Values of co-primes a and b are (1, 15), (3, 5)
So, the two digit number are 12 x 3 and 12 x 5 i.e. 36 and 60 .
Correct Answer: 27, 189
Explanation:
Let the number be 27a and 27b
Then, 27a + 27b = 216
or a + b = 216/27 = 8
? Values of co-primes with sum 8 are (1, 7) and (3, 5)
So, the number are (27 x 1 , 27 x 7) i.e. (27, 189)
Correct Answer: 35 cm
Explanation:
Required length = H.C.F of 700, 385, 1295 cm
= 35 cm.
Correct Answer: 12
Explanation:
Find the H.C.F. of 84 and 180, which is 12 and this is the required answer .
Correct Answer: 39
Explanation:
The L.C.M of 9, 10, 15 = 90
On dividing 1936 by 90, the remainder = 46
But a part of this remainder = 7
Hence, the two numbers = 46 - 7 = 39.
Correct Answer: 320
Explanation:
Product of two numbers = LCM of two numbers x HCF of two numbers.
? 1600 = LCM x 5
? LCM = 320
Correct Answer: No such pair exists
Explanation:
H.C.F. of two numbers divides their L.C.M. exactly. Since 16 is not a factor of 136, it states that there does not exist any pair of numbers with H,C.F. 16 and L.C.M. 136.
Correct Answer: 995
Explanation:
Here (16 - 3) = 13,
(18 - 5) = 13 and
(21 - 8 ) = 13
So, required number = (L . C . M of 16, 18, 21) - 13
= (1008 - 13)
= 995
Correct Answer: 9828
Explanation:
Required number is divisible by the L . C . M of 12, 18, 21, 28 i.e 252.
Now, greatest number of four digits = 9999
On dividing 9999 by 252, the remainder is 171
? Required number = (9999 - 171) = 9828.
Correct Answer: 1897
Explanation:
Required Number = (LCM of 15, 27, 35 and 42) + 7
= 1890 + 7
= 1897
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