3/7
L. C . M of 2/7, 3/14 and 5/ 3 = ( LCM of 2, 3 and 5) / ( HCF of 7, 14 and 3)
= 30
Straight forward answer 12, 24, 36
The difference of requisite number must be 12 and each one must be divisible by 12, so the numbers are 84, 96.
The largest number is the H.C.F. of 210, 315, 147, and 168, which is 21.
H.C.F of 1485 and 4356 is 99
7/9, 5/7, 3/5
Required number = (L . C . M of 21, 28, 36, 45 ) + 3
= (1260 + 3 )
= 1263
The number of prime factors in the given product
= (222 + 333 + 555)
= 1110.
First number = 2 x 44 = 88
Second number = (LCM x HCF ) / First number
? Second number = 44 x 264 / 88 = 132.
Let the numbers be 2x and 3x.
So, their LCM = 6x
However, the LCM is given as 48
? 6x = 48
? x=8
So, the numbers are 16 and 24.
Hence, their sum is 40.
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