If (x+2) is the HCF of x2 + ax + b and x2 + cx + d.
Then, (-2)2 -2a +b = (-2)2 -2c + d
b + 2c = 2a + d
The required greatest number is the HCF of 263-7, 935-7, 1383-7
i.e. 256, 928 and 1376 HCF = 32
Here , x = a ? b, y = b ? c, z = c ? a
We have x + y + z = a ? b + b ? c + c ? a = 0
? x3 + y + z ? 3xyz = 0
Hence , the numerical value of algebraic expression is 0 .
The shaded region represents
y ? x
Minimum value of x2 + |
|
- 3 is |
x2 + 1 |
We have p3 + q3 + r3 ? 3pqr = (p + q + r) (p2 + q2 + r2 ?pq ? qr - rp)
Here p = a ? 4, q = b ? 3, r = c ?1
So, given expression is (p + q + r) (p2 + q2 + r2 ? pq ? qr ? rp)
= (a ? 4 + b ? 3 + c ? 1) (p2 + q2 + r2 ? pq ? qr ? rp)
= (a + b + c ? 8) (p2 + q2 + r2 ? pq ? qr ? rp)
= (8 ? 8) (p2 + q2 + r2 ? pq ? qr ? rp)
? (a ? 4)3 + (b ? 3)3 + (c ? 1)3 ? 3 (a ? 4) (b ? 3) (c ? 1) = 0
Required measure = HCF of 403, 434 and 465
= 31 cm
7 / 8 = 0.875,
6 / 7 = 0.857,
4 / 5 = 0.8 and 5/6 = 0.833
Now, 0.875 > 0.857 > 0.833 > 0.8
So, 7/8 is the greatest
L.C.M = ( L.C.M . of 2, 4, 5, 7) / (H.C.F. of 3, 9, 6, 12)
= 140/3
L. C . M = ( L.C.M of 3, 6, 9 ) / (H.C.F of 4, 7, 8)
= 18 / 1
= 18
H.C.F = ( H.C.F of 1, 3 , 5, 7, 9) / (L.C.M of 2, 4, 6, 8 , 10)
= 1 / 120
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