As per the given question , we have
a2 + b2 + c2 = 2 (a b c) 3
⇒ a2 + b2 + c2 = 2a + 2b + 2c + 3 = 0
⇒ a2 2a + 1 + b2 + 2b + 1 + c2 + 2c + 1 = 0
⇒ (a 1)2 + (b + 1)2 + (c + 1)2 = 0
[If x2 + y2 + z2 = 0 ⇒ x = 0; y = 0; z = 0]
∴ a 1 = 0 ⇒ a = 1
b + 1 = 0 ⇒ b = 1
c + 1 = 0 ⇒ c = 1
∴ 2a 3b + 4c = 2 + 3 4 = 1
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 χ 19.999
? ? ? 750 χ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
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