Let the two numbers be P and Q.
According to given question,
Sum of two numbers = 24
? P + Q = 24 ...................... (1)
Product of two numbers = 143
and, PQ = 143 .......................... (2)
As we know the formula,
? P 2 + Q2 = (P + Q)2 ? 2PQ
Put the value from the equation (1) and (2), We will get
? P 2 + Q2 = (24)2 ? 2 × 143
? P 2 + Q2 = 576 ? 286 = 290
Let two alternate odd integers odd integers be (2x+1) and (2x+5).
Then according to the question,
(2x + 1) (2x + 5) = 3(2x + 1) + 12
? (2x + 1) (2x + 5 - 3) = 12
? 2x2 + 3x - 5 = 0
On solving this quadratic equation,we get
x = 1 and x = -5/2
x = -5/2 is not a integer ? x = 1
Then, larger integer = 2x + 5 = 2 x 1 + 5 = 7
x - y = 0.9 ...(i)
and 11(x + y)-1=2
? 11/ (x + y) = 2
? 2(x + y) =11
? x + y = 11/2 ...(ii)
On solving Eqs.(i) and (ii),we get
x = 3.2
and y = 2.3
x = 1 + ?2
? x4 - 4x3 + 4x2 = x2(x2 - 4x + 4)
= x2(x - 2)2
= (1 + ?2)2(1 + ?2 - 2)2
=(?2 + 1)2 (?2 - 1)2
=[(?2)2 - (1)2]2
=(2 - 1)2 =1
x3 + 1 + 2x =6x + 1/x
x3 + 1 + 2x = (6x2 + 1)/x
(x3 + 1 + 2x)x = 6x2 + 1
x4 - 4x2 - 6x2 -1 =0
x4 - 4x2 + x - 1 =0
Degree of polynomial is highest exponent degree term i.e.,4.
If (5x2 ? 3y2) : xy = 11 : 2, then the positive value of |
|
is : |
y |
As we know from the algebra formula,
(a ? b)3 = a3 ? b 3 ? 3ab (a ? b) .......................(1)
As per given question,
a3 ? b 3 = 56 and a ? b = 2
Put these value in above equation (1) . We will get,
? 23 = 56 ? 3ab x 2
? 8 = 56 ? 3ab x 2
? 8 = 56 ? 6ab
? 6ab = 56 ? 8 = 48
? ab = 8 ...................... (i)
? a2 + b2 = (a ? b)2 + 2ab
? a2 + b2 = (a ? b)2 + 2ab
Put the value of
? a2 + b2 = 22 + 2 x 8
? a2 + b2 = 4 + 16 = 20
If x = 2 + ?3, then the value of ?x + |
|
is : |
?x |
If 5a + |
|
= 5, the value of 9a2 + |
|
is |
3a | 25a2 |
Given that :-
Now ,a3 + b3 + c3 = 3abc
( a+b+c )( a2 + b2 + c2 - ab - bc - ca ) + 3abc = 3abc
( a+b+c )( a2 + b2 + c2 - ab - bc - ca ) = 0
∴ a² + b² + c² - ab - bc - ca = 0 or a + b + c ≠ 0
Where ,
a = b = c
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