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  • Question
  • If in a long division sum,the dividend is 380606 and the successive remainders from the first to the last are 434, 125 and 413, then the divisor is?


  • Options
  • A. 451
  • B. 843
  • C. 4215
  • D. 3372

  • Correct Answer
  • 843 

    Explanation

    Let d = divisor and q = quotient

    First remove the last remainder:
    d x q + 413 = 380606
    d x q = 380193

    So d cannot be even (choice d) or a multiple of 5 (choice c).

    If we try choice a or b,
    a quick division (by calculator) shows that
    380193 = 451 x 843, the other two choices.

    (In the absence of choices, we could find the prime factors of 380193,
    which are 3 x 11 x 41 x 281 and get various candidate divisors from that.)

    So one of them is the divisor and the other the quotient.

    So we can just check the first remainder:
    843 x 4 = 3372
    3806 - 3372 = 434 ... a match!

    And just to be sure:
    451 x 8 = 3608
    3806 - 3608 = 198

    So the divisor is 843.


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