logo

CuriousTab

CuriousTab

Discussion


Home Digital Electronics Number Systems and Codes Comments

  • Question
  • The decimal equivalent of the BCD number 1010 is ________.


  • Options
  • A. 8
  • B. 10
  • C. 12
  • D. invalid

  • Correct Answer
  • invalid 


  • Number Systems and Codes problems


    Search Results


    • 1. An unweighted code in which only one bit changes from one code number to the next is ________.

    • Options
    • A. BCD
    • B. Excess-3
    • C. Gray
    • D. ASCII
    • Discuss
    • 2. Decimal 474 is ________ in BCD.

    • Options
    • A. 0100 0111 0100
    • B. 0100 1011 0101
    • C. 0100 1001 0011
    • D. 0110 1011 1001
    • Discuss
    • 3. Hexadecimal 44 is ________ in decimal.

    • Options
    • A. 6810
    • B. 7410
    • C. 7710
    • D. 9810
    • Discuss
    • 4. The largest BCD number that can be represented with four binary bits is ________.

    • Options
    • A. 9
    • B. 10
    • C. 15
    • D. 16
    • Discuss
    • 5. The decimal fraction 1/4 can be written in binary as________.

    • Options
    • A. 0.010
    • B. 0.100
    • C. 0.110
    • D. 0.011
    • Discuss
    • 6. Hexadecimal 44 is ________ in binary.

    • Options
    • A. 01000100
    • B. 10011010
    • C. 01011000
    • D. 10001100
    • Discuss
    • 7. Hexadecimal 16 is ________ in decimal.

    • Options
    • A. 3210
    • B. 2210
    • C. 2510
    • D. 2710
    • Discuss
    • 8. Hexadecimal AA is ________ in decimal.

    • Options
    • A. 16510
    • B. 17010
    • C. 18610
    • D. 17616
    • Discuss
    • 9. A complete alphanumeric code would include 26 lowercase letters, 26 uppercase letters, 10 numeric digits, 7 punctuation marks, and anywhere from ________ to ________ other characters.

    • Options
    • A. 5, 10
    • B. 10, 15
    • C. 10, 20
    • D. 20, 40
    • Discuss
    • 10. Adding a zero to the leftmost bit of an ASCII code is called ________.

    • Options
    • A. extra zero
    • B. zero padding
    • Discuss


    Comments

    There are no comments.

Enter a new Comment