Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:Reset sequencing is critical when bringing a microcontroller into a known state. For the 8051 family, understanding the polarity and duration of the reset signal prevents intermittent startup faults and undefined behavior.
Given Data / Assumptions:
Concept / Approach:The 8051’s RST input is active-high. A logic high applied to RST for at least two machine cycles (with the clock oscillating) forces the CPU to reset registers, set PC to reset vector, and place I/O in default states. This behavior is uniform across common 8051 derivatives.
Step-by-Step Solution:
Confirm polarity: RST is active-high.Apply timing rule: keep RST high for ≥ 2 machine cycles.Ensure oscillator is active so timing is honored.On deassertion, code execution begins at the reset vector (0000h).Verification / Alternative check:Datasheets specify RST timing diagrams showing minimum high duration and that a low level releases reset. External RC networks or supervisor ICs are commonly used to satisfy these conditions during power-up.
Why Other Options Are Wrong:
Common Pitfalls:Using too-short reset pulses; relying solely on slow power ramps without a POR circuit; ignoring oscillator startup time before releasing reset.
Final Answer:Correct
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