If the voltage in the given circuit was cut in half, what would the current equal?
By Ohm's law, V = IR. I = V/R Given, Four 90 ohm resisters in series. So, R = ( R1 + R2 + R3 + R4) = 4 x 90 = 360 ohms. Therefore, I = 18/360 = 0.05 A [or] 50 milli amps.
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