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  • Question

  • If four 90 Ω resistors are connected in series across an 18 V source, the current equals ___.


  • Options
  • A. 50 mA
  • B. 0.2 A
  • C. 5 A
  • D. 20 A

  • Correct Answer
  • 50 mA 

    Explanation 
    By Ohm's law, V = IR.

I = V/R

Given, Four 90 ohm resisters in series. 

So, R = ( R1 + R2 + R3 + R4) = 4 x 90 = 360 ohms.

Therefore, I = 18/360 = 0.05 A [or] 50 milli amps.

    • More questions

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    • Options
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    • 2. Capacitive reactance is inversely proportional with frequency.

    • Options
    • A. True
    • B. False
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    • 3. What is the average value of a 12 V peak wave?

    • Options
    • A. 3.82 V
    • B. 4.24 V
    • C. 7.64 V
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    • 4. The DIAC is a:

    • Options
    • A. transistor
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    • C. three-layer device
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    • 5. Phase angle is the difference in phase between the applied voltage (VS) and the circuit current (IT).

    • Options
    • A. True
    • B. False
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    • 6. Which is considered to be the common reference for a parallel circuit?

    • Options
    • A. Voltage
    • B. Current
    • C. Power
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      • Discuss
    • 7. 0.00015 V can be expressed in powers of ten as 1.5 × 10?4 V.

    • Options
    • A. True
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      • Discuss
    • 8. A 10 µF capacitor will have more capacitive reactance than a 20 µF capacitor in a 60 Hz circuit.

    • Options
    • A. True
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      • Discuss
    • 9. A JFET can be either a current-controlled device or a voltage-controlled device.

    • Options
    • A. True
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    • 10. The effectiveness of a filter in rejecting signals beyond cutoff frequency is a function of the filter roll-off rating.

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