The power rating for the resistor in the given circuit should be at least __

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Home ‣ Electronics ‣ Ohm's Law Comments

Question
The power rating for the resistor in the given circuit should be at least ___.
Options
A. 1/4 W
B. 1/2 W
C. 1 W
D. 2 W

Correct Answer

1/2 W

Ohm's Law problems

Search Results

1. If the voltage across a resistor ___, the current flowing through it will increase.
Options
A. increases
B. decreases
C. stays the same
D. Not enough information

Discuss

Correct Answer: increases

2. The ___ rating of a resistor will increase with an increase in the surface area of the resistor.
Options
A. resistance
B. current
C. power
D. voltage

Discuss

Correct Answer: power

3. The voltage across a ___ resistor is 12 V and the current through it is 500 µA.
Options
A. 600 Ω
B. 2.4 kΩ
C. 6 kΩ
D. 24 kΩ

Discuss

Correct Answer: 24 kΩ

4. ___ is a better way of expressing 7,500,000 W.
Options
A. 7.5 kW
B. 7,500 MW
C. 7,500 GW
D. 7.5 MW

Discuss

Correct Answer: 7.5 MW

5. Using 4 kWh of power is equivalent to using 2000 W of power for 2 h.
Options
A. True
B. False

Discuss

Correct Answer: True

6.

The power rating for the resistor in the given circuit should be at least ______.
Options
A. 1/4 W
B. 1/2 W
C. 1 W
D. 2 W

Discuss

Correct Answer: 2 W

7. Resistance and current are _________.
Options
A. directly proportional
B. inversely proportional
C. not related
D. similar to voltage

Discuss

Correct Answer: inversely proportional

8. The number of joules used in 1 second is always equal to the number of _______.
Options
A. siemens
B. coulombs
C. amperes
D. watts

Discuss

Correct Answer: watts

9. The power is ___ if 200 J of energy are used in 10 s.
Options
A. 2 W
B. 5 W
C. 20 W
D. 50 W

Discuss

Correct Answer: 20 W

10.

The voltage supplying the current in the given circuit is _____.
Options
A. 2.5 V
B. 25 V
C. 250 V
D. 2.5 kV

Discuss

Correct Answer: 25 V

Explanation:

V = IR

= 250 x 10^-6 x 100 x 10^3

= 250 x 100 x 10^(-6+3)

= 250 x 100 x 10^-3

= 25 x 1000 x 10^-3

= 25 x 10^3 x 10^-3

= 25 x 10^0

= 25 x 1 [Anything power 0 is 1]

= 25 volts.

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Ohm's Law problems

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