In filtration theory, what is the compressibility coefficient (s) for an absolutely compressible filter cake?

Difficulty: Easy

Correct Answer: 1

Explanation:

Introduction / Context:Filter cake compressibility is central to predicting how specific cake resistance changes with applied pressure in constant-pressure or constant-rate filtration. The compressibility coefficient s (sometimes n) characterises the sensitivity of cake resistance to pressure.

Given Data / Assumptions:

  • Definition: α = α_0 * (ΔP)^s, where α is specific cake resistance and s is the compressibility coefficient.
  • Absolutely compressible cake implies maximum sensitivity to pressure.
  • Absolutely incompressible cake implies no sensitivity to pressure.

Concept / Approach:By convention, s = 0 corresponds to an incompressible cake (α independent of ΔP). As compressibility increases, s increases toward unity. An absolutely compressible cake exhibits a direct proportionality of resistance to pressure on a log-log basis with slope equal to 1.

Step-by-Step Solution:

Start from α = α_0 * (ΔP)^s.For absolutely compressible cake, resistance scales linearly with ΔP in log space, hence s = 1.For absolutely incompressible cake, s = 0 for comparison.

Verification / Alternative check:Experimental plots of ln(α) versus ln(ΔP) give slope s. Highly compressible colloidal cakes show slopes close to 1, matching the limiting idealisation.

Why Other Options Are Wrong:

0 denotes incompressible cake.“Between 0 and 1” is true for partially compressible cakes but not for the absolute case.“∞” and “Depends only on pressure drop” are non-physical or vague in this context.

Common Pitfalls:Confusing s with porosity exponent; misreading absolute compressibility as infinite resistance instead of maximum pressure sensitivity.

Final Answer:1

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