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  • Question
  • Which of the following holds good for a solution obeying Raoult's law (i.e., an ideal solution) (where, ?H = heat of mixing, and ?V = volume change on mixing )?


  • Options
  • A. ?H = 1 (+ ve)and ? V = -ve
  • B. ?H = 0
  • C. ?V = 0
  • D. both (b) and (c)

  • Correct Answer
  • both (b) and (c) 


  • Stoichiometry problems


    Search Results


    • 1. Enthalpy of formation of NH3 is - 46 kJ/kg mole. The enthalpy change for the gaseous reaction, 2NH3 ? N2 + 3H2, is equal to __________ kJ/kg. mole.

    • Options
    • A. 46
    • B. 92
    • C. -23
    • D. -92
    • Discuss
    • 2. Ideal solution is formed, when its components have zero

    • Options
    • A. heat of mixing.
    • B. volume change.
    • C. both (a) & (b).
    • D. neither (a) nor (b).
    • Discuss
    • 3. The vapor pressures of benzene and toluene are 3 and 4/3 atmospheres respectively. A liquid feed of 0.4 moles of benzene and 0.6 moles of toluene is vapourised. Assuming that the products are in equilibrium, the vapor phase mole fraction of benzene is

    • Options
    • A. 0.4
    • B. 0.6
    • C. 0.8
    • D. 0.2
    • Discuss
    • 4. Percentage saturation of a vapor bearing gas is always __________ the relative saturation.

    • Options
    • A. higher than
    • B. smaller than
    • C. equal to
    • D. either (a) or (b); depends on the system
    • Discuss
    • 5. 1 gm mole of methane (CH4) contains

    • Options
    • A. 6.02 x 1023 atoms of hydrogen.
    • B. 4 gm atoms of hydrogen.
    • C. 3.01 x 1023 molecules of methane.
    • D. 3 gms of carbon.
    • Discuss
    • 6. Pick out the wrong unit conversion of mass transfer co-efficient.

    • Options
    • A. 1 lb/hr.ft3.atm. = 4.8182 kg/hr.m2.bar
    • B. 1 kg/hr.m2.atm= 0.98687 kg/hr. m .bar
    • C. 1 lb/hr . ft2 = 4.8823 kg/hr . m2
    • D. 1 kg/hr . m2 = 4.8823 lb/hr . ft2
    • Discuss
    • 7. Diffusion is that property by virtue of which a perfume bottle when opened up in a room, makes the whole room fragrant with its smell. If a perfume 'X' diffuses twice as fast as another perfume 'Y'; what is the molecular weight of 'Y', if the vapor density of gas 'X' is 2? Molecular weight of gas 'X' is to be assumed to be 2.

    • Options
    • A. 2
    • B. 4
    • C. 8
    • D. 16
    • Discuss
    • 8. The temperature of a gas in a closed container is 27° C. If the temperature of the gas is incresed to 300° C, then the pressure exerted is

    • Options
    • A. doubled.
    • B. halved.
    • C. trebled.
    • D. unpredictable.
    • Discuss
    • 9. Addition of a non-volatile solute to a solvent produces a __________ in its solvent.

    • Options
    • A. freezing point elevation
    • B. boiling point depression
    • C. vapor pressure lowering
    • D. all (a), (b) & (c)
    • Discuss
    • 10. Pick out the wrong unit conversion of heat transfer co-efficient.

    • Options
    • A. 1 kcal/m2.hr.°C = 0.2048 BTU/ft2.hr. °F. = 1.163 W/m2.°K
    • B. 1 kcal/m2.hr.°K = 1.163 W/m2.°C
    • C. 1 W/m2 . °C = 0.1761 BTU/ft2.hr.°F.
    • D. 1 BTU/ft2.hr.°F = 4.88 kcal/m2.hr.°C = 20.44 kJ/m2.hr°C = 5.678 W/m2.°C.
    • Discuss


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