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- Question
The usual method(s) to solve rate equation of simple enzyme kinetics is/are
Options- A. Michaelis Menten approach
- B. Briggs-Haldane approach
- C. Numerical solution approach
- D. all of these
- Correct Answer
- all of these
- 1. The power required by an agitator operating in a gas-sparged system is
Options- A. lesser than the power required by an impeller in operating at same speed in a gas free system
- B. more than the power required by an impeller in operating at same speed in a gas free system
- C. same as the power required by an impeller in operating at same speed in a gas free system
- D. none of the above Discuss
- 2. The monod model predicts that the specific growth rate
Options- A. will increase with the concentration of the growth limiting substrate until it reaches a maximum value
- B. will decrease with the concentration of the growth limiting substrate
- C. will increase with the concentration of the growth limiting substrate
- D. does not depend on growth limiting substrate Discuss
- 3. The ratio of the amount of a protein present in a sample, which is used as a measure of purification, is known as
Options- A. specific activity
- B. relative activity
- C. purity ratio
- D. all of these Discuss
- 4. Which category of enzymes belongs to class 5 in the international classification?
Options- A. Hydrolases
- B. Isomerases
- C. Oxido-reductases
- D. Cyclase Discuss
- 5. The water being used in dairy industry should contain not more than
Options- A. 5 proteolytic and/or lipolytic organisms per ml
- B. 10 proteolytic and/or lipolytic organisms per ml
- C. 15 proteolytic and/or lipolytic organisms per ml
- D. 20 proteolytic and/or lipolytic organisms/ml Discuss
- 6. The initial velocity, V0, of an enzyme catalyzed reaction reaches Vmax as
Options- A. [S] = KM
- B. [S] = 10 * KM
- C. 1/[S] = 1/KM
- D. 1/[S] ? 0 Discuss
- 7. Predominantly uncompetitive inhibition may be called when
Options- A. competitive inhibition is greater than uncompetitive inhibition
- B. competitive inhibition is smaller than uncompetitive inhibition
- C. competitive inhibition is equal to uncompetitive inhibition
- D. none of the above Discuss
- 8. If a reaction occurs in the absence of inhibitor with rate ?0 and in the presence of inhibitor with rate ?i, the degree of inhibition is defined as
Options- A. (?0 - ?i)/?0
- B. (?0 + ?i)/?0
- C. (?0?i)/?0
- D. (?0-?i)/?i Discuss
- 9. A classical noncompetitive inhibitor has
Options- A. no effect on substrate binding
- B. no effect on substrate binding and vice versa
- C. significant effect on substrate binding
- D. significant effect on substrate binding and vice versa Discuss
- 10. Which of the following step is assumed to be the slowest step in the Michaelis Menten equation?
Options- A. The substrate consuming step
- B. The product releasing step
- C. Formation of enzyme substrate complex
- D. None of these Discuss
More questions
Correct Answer: lesser than the power required by an impeller in operating at same speed in a gas free system
Correct Answer: will increase with the concentration of the growth limiting substrate until it reaches a maximum value
Correct Answer: specific activity
Correct Answer: Isomerases
Correct Answer: 5 proteolytic and/or lipolytic organisms per ml
Correct Answer: 1/[S] ? 0
Correct Answer: competitive inhibition is greater than uncompetitive inhibition
Correct Answer: (?0 - ?i)/?0
Correct Answer: no effect on substrate binding and vice versa
Correct Answer: The product releasing step
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