#include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(20); printf("%d\n", sizeof(p)); free(p); return 0; }
#include<stdio.h> int main() { int a = 300, b, c; if(a >= 400) b = 300; c = 200; printf("%d, %d, %d\n", a, b, c); return 0; }
#include<stdio.h> int main() { int x = 10, y = 20; if(!(!x) && x) printf("x = %d\n", x); else printf("y = %d\n", y); return 0; }
Step 1: if(!(!x) && x)
Step 2: if(!(!10) && 10)
Step 3: if(!(0) && 10)
Step 3: if(1 && 10)
Step 4: if(TRUE) here the if condition is satisfied. Hence it prints x = 10.
#include<stdio.h> int main() { enum status {pass, fail, absent}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = absent; stud3 = fail; printf("%d %d %d\n", stud1, stud2, stud3); return 0; }
#include<stdio.h> int main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for(i=0; i<=9; i++) scanf("%s %f", e[i].name, &e[i].sal); return 0; }
Sample output: Turbo C (Windows)
c:\>myprogram Sample 12.123 scanf : floating point formats not linked Abnormal program termination
struct emp { char *n; int age; }; struct emp e={"CuriousTab", 15}; FILE *fp; fwrite(&e, sizeof(e), 1, fp);
#include<stdio.h> #include<string.h> int main() { char *s; char *fun(); s = fun(); printf("%s\n", s); return 0; } char *fun() { char buffer[30]; strcpy(buffer, "RAM"); return (buffer); }
#include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }
If you compile the same program in 32 bit platform like Linux (GCC Compiler) it may allocate the required memory.
int (*pf)();
#include<stdio.h> int main() { char str[] = "peace"; char *s = str; printf("%s\n", s++ +3); return 0; }
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