What will be the output of the program (sample.c) given below if it is executed from the command line?
cmd> sample monday tuesday wednesday thursday

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    while(--argc>0)
        printf("%s", *++argv);
    return 0;
}

/* myprog.c */
#include<stdio.h>
#include<stdlib.h>

int main(int argc, char **argv)
{
    int i;
    for(i=1; i<=3; i++)
        printf("%u\n", &argv[i]);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    printf("%c", *++argv[2] );
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    printf("%s\n", argv[0]);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    int j;
    j = argv[1] + argv[2] + argv[3];
    printf("%d", j);
    return 0;
}

/* myprog.c */
#include<stdio.h>

int main(int argc, char **argv)
{
    printf("%c\n", **++argv);
    return 0;
}

/* myprog.c */
#include<stdio.h>

int main(int argc, char **argv)
{
    int i;
    for(i=0; i<argc; i++)
        printf("%s\n", argv[i]);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    printf("%d %s", argc, argv[1]);
    return 0;
}

/* sample.c */
#include<stdio.h>
#include<dos.h>

int main(int arc, char *arv[])
{
    int i;
    for(i=1; i<_argc; i++)
        printf("%s ", _argv[i]);
    return 0;
}

#include<stdio.h>
#include<string.h>

int main()
{
    char *s;
    char *fun();
    s = fun();
    printf("%s\n", s);
    return 0;
}
char *fun()
{
    char buffer[30];
    strcpy(buffer, "RAM");
    return (buffer);
}

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *p;
    p = (int *)malloc(256 * 256);
    if(p == NULL)
        printf("Allocation failed");
    return 0;
}