Addresses of argv elements (pointers) and their contiguity: predict subsequent &argv[i] values. /* myprog.c / #include <stdio.h> #include <stdlib.h> int main(int argc, char argv) { int i; for (i = 1; i <= 3; i++) printf("%u ", (unsigned)&argv[i]); return 0; } Given that the first printed address is 65517, find the next two values.

Introduction / Context:
This problem focuses on how argv is laid out in memory: it is an array of pointers (char). Taking &argv[i] yields the address of the i-th pointer object within that array. Consecutive pointer objects are stored contiguously, so their addresses differ by sizeof(char).

Given Data / Assumptions:

• Architecture consistent with 16-bit model where sizeof(char) = 2 bytes for the displayed addresses.
• First printed value (address of argv[1]) is 65517.
• The code prints &argv[1], then &argv[2], then &argv[3].

Concept / Approach:
Since argv is an array of pointers, &argv[i+1] = &argv[i] + 1 * sizeof(char*). With sizeof(char*) = 2, each subsequent address increases by 2.

Step-by-Step Solution:

Verification / Alternative check:
On systems with 4-byte pointers, the increments would be +4 instead; the question fixes the first value to imply a 2-byte stride.

Why Other Options Are Wrong:

• 65525 65531 / 65521 65525: Use a 4-byte stride inconsistent with the given context.
• 65517 65517: Implies no increment, which is incorrect for an array of distinct elements.

Common Pitfalls:
Confusing &argv[i] (address of the pointer element) with argv[i] (address of the string). These are different layers.

Final Answer:
65519 65521