What will be the output of the program if it is executed like below?
cmd> sample

/* sample.c */
#include<stdio.h>

int main(int argc, char **argv)
{
    printf("%s\n", argv[argc-1]);
    return 0;
}

#include<stdio.h>
#include<malloc.h>

struct emp
{
    int len;
    char name[1];
};
int main()
{
    char newname[] = "Rahul";
    struct emp *p = (struct emp *) malloc(sizeof(struct emp) -1 +
                    strlen(newname)+1);

    p->len = strlen(newname);
    strcpy(p -> name, newname);
    printf("%d %s\n", p->len, p->name);
    return 0;
}

typedef struct s
{
    int a;
    float b;
}s;

/* myprog.c */
#include<stdio.h>
#include<stdlib.h>

int main(int argc, char **argv)
{
    printf("%s\n", *++argv);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int sizeofargv, char *argv[])
{
    while(sizeofargv)
        printf("%s", argv[--sizeofargv]);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, int *argv)
{
    int i;
    for(i=1; i<argc; i++)
        printf("%s\n", argv[i]);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    printf("%c", **++argv);
    return 0;
}

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    int i=0;
    i+=strlen(argv[1]);
    while(i>0)
    {
        printf("%c", argv[1][--i]);
    }
    return 0;
}