Curioustab

Home » C Programming » Command Line Arguments

What will be the output of the program if it is executed like below? cmd> sample /* sample.c */ #include int main(int argc, char **argv) { printf("%s\n", argv[argc-1]); return 0; }

0
sample
samp
No output

Correct Answer: sample

Next Question→

More Questions from Command Line Arguments

What will be the output of the program (myprog.c) given below if it is executed from the command line? cmd> myprog one two three /* myprog.c */ #include #include int main(int argc, char **argv) { printf("%s\n", *++argv); return 0; }
What will be the output of the program (sample.c) given below if it is executed from the command line? cmd> sample friday tuesday sunday /* sample.c */ #include int main(int sizeofargv, char *argv[]) { while(sizeofargv) printf("%s", argv[--sizeofargv]); return 0; }
What will be the output of the program (sample.c) given below if it is executed from the command line? cmd> sample "*.c" /* sample.c */ #include int main(int argc, int *argv) { int i; for(i=1; i

What will be the output of the program (myprog.c) given below if it is executed from the command line? cmd> myprog one two three /* myprog.c */ #include int main(int argc, char *argv[]) { int i; for(i=1; i

What will be the output of the program (myprog.c) given below if it is executed from the command line? cmd> myprog 1 2 3 /* myprog.c */ #include #include int main(int argc, char **argv) { int i, j=0; for(i=0; i

What will be the output of the program #include void fun(int); int main(int argc) { printf("%d ", argc); fun(argc); return 0; } void fun(int i) { if(i!=4) main(++i); }

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion