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  • Question
  • Point out the error in the program?
    #include<stdio.h>
    #include<string.h>
    void modify(struct emp*);
    struct emp
    {
        char name[20];
        int age;
    };
    int main()
    {
        struct emp e = {"Sanjay", 35};
        modify(&e);
        printf("%s %d", e.name, e.age);
        return 0;
    }
    void modify(struct emp *p)
    {
         p ->age=p->age+2;
    }
    


  • Options
  • A. Error: in structure
  • B. Error: in prototype declaration unknown struct emp
  • C. No error
  • D. None of above

  • Correct Answer
  • Error: in prototype declaration unknown struct emp 

    Explanation
    The struct emp is mentioned in the prototype of the function modify() before declaring the structure.To solve this problem declare struct emp before the modify() prototype.

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    • 1. Point out the error in the program?
      #include<stdio.h>
      
      int main()
      {
          struct a
          {
              float category:5;
              char scheme:4;
          };
          printf("size=%d", sizeof(struct a));
          return 0;
      }
      

    • Options
    • A. Error: invalid structure member in printf
    • B. Error in this float category:5; statement
    • C. No error
    • D. None of above
    • Discuss
    • 2. Point out the error in the program?
      struct emp
      {
          int ecode;
          struct emp *e;
      };
      

    • Options
    • A. Error: in structure declaration
    • B. Linker Error
    • C. No Error
    • D. None of above
    • Discuss
    • 3. Point out the error in the program?
      #include<stdio.h>
      
      int main()
      {
          struct emp
          {
              char name[25];
              int age;
              float bs;
          };
          struct emp e;
          e.name = "Suresh";
          e.age = 25;
          printf("%s %d\n", e.name, e.age);
          return 0;
      }
      

    • Options
    • A. Error: Lvalue required/incompatible types in assignment
    • B. Error: invalid constant expression
    • C. Error: Rvalue required
    • D. No error, Output: Suresh 25
    • Discuss
    • 4. Point out the error in the program?
      #include<stdio.h>
      
      int main()
      {
          struct emp
          {
              char n[20];
              int age;
          };
          struct emp e1 = {"Dravid", 23};
          struct emp e2 = e1;
          if(e1 == e2)
              printf("The structure are equal");
          return 0;
      }
      

    • Options
    • A. Prints: The structure are equal
    • B. Error: Structure cannot be compared using '=='
    • C. No output
    • D. None of above
    • Discuss
    • 5. Point out the error in the program?
      #include<stdio.h>
      
      int main()
      {
          struct emp
          {
              char name[20];
              float sal;
          };
          struct emp e[10];
          int i;
          for(i=0; i<=9; i++)
              scanf("%s %f", e[i].name, &e[i].sal);
          return 0;
      }
      

    • Options
    • A. Error: invalid structure member
    • B. Error: Floating point formats not linked
    • C. No error
    • D. None of above
    • Discuss
    • 6. Point out the error in the program in 16-bit platform?
      #include<stdio.h>
      
      int main()
      {
          struct bits
          {
              int i:40;
          }bit;
      
          printf("%d\n", sizeof(bit));
          return 0;
      }
      

    • Options
    • A. 4
    • B. 2
    • C. Error: Bit field too large
    • D. Error: Invalid member access in structure
    • Discuss
    • 7. Nested unions are allowed

    • Options
    • A. True
    • B. False
    • Discuss
    • 8. A structure can be nested inside another structure.

    • Options
    • A. True
    • B. False
    • Discuss
    • 9. Union elements can be of different sizes.

    • Options
    • A. True
    • B. False
    • Discuss
    • 10. The '->' operator can be used to access structures elements using a pointer to a structure variable only

    • Options
    • A. True
    • B. False
    • Discuss


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