What will be the output of the program if the array begins 1200 in memory? #include int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u ", arr, &arr[0], &arr); return 0; }

Question

What will be the output of the program if the array begins 1200 in memory? #include<stdio.h>

int main()
{
    int arr[]={2, 3, 4, 1, 6};
    printf("%u, %u, %u
", arr, &arr[0], &arr);
    return 0;
}

Accepted Answer

Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized. Step 2: printf("%u, %u, %u
", arr, &arr[0], &arr); Here, The base address of the array is 1200. => arr, &arr is pointing to the base address of the…

What will be the output of the program if the array begins 1200 in memory? #include int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u\n", arr, &arr[0], &arr); return 0; }

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