What will be the output of the program? #include int main() { void fun(int, int[]); int arr[] = {1, 2, 3, 4}; int i; fun(4, arr); for(i=0; i<4; i++) printf("%d,", arr[i]); return 0; } void fun(int n, int arr[]) { int *p=0; int i=0; while(i++ < n) p = &arr[i]; *p=0; }

Step 1: void fun(int, int[]); This prototype tells the compiler that the function fun() accepts one integer value and one array as an arguments and does not return anything.

Step 2: int arr[] = {1, 2, 3, 4}; The variable a is declared as an integer array and it is initialized to

a[0] = 1, a[1] = 2, a[2] = 3, a[3] = 4

Step 3: int i; The variable i is declared as an integer type.

Step 4: fun(4, arr); This function does not affect the output of the program. Let's skip this function.

Step 5: for(i=0; i<4; i++) { printf("%d,", arr[i]); } The for loop runs untill the variable i is less than '4' and it prints the each value of array a.

Hence the output of the program is 1,2,3,4