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What will be the output of the program? #include
int main() { static int arr[] = {0, 1, 2, 3, 4}; int *p[] = {arr, arr+1, arr+2, arr+3, arr+4}; int **ptr=p; ptr++; printf("%d, %d, %d\n", ptr-p, *ptr-arr, **ptr); *ptr++; printf("%d, %d, %d\n", ptr-p, *ptr-arr, **ptr); *++ptr; printf("%d, %d, %d\n", ptr-p, *ptr-arr, **ptr); ++*ptr; printf("%d, %d, %d\n", ptr-p, *ptr-arr, **ptr); return 0; }
0, 0, 0 1, 1, 1 2, 2, 2 3, 3, 3
1, 1, 2 2, 2, 3 3, 3, 4 4, 4, 1
1, 1, 1 2, 2, 2 3, 3, 3 3, 4, 4
0, 1, 2 1, 2, 3 2, 3, 4 3, 4, 5
Correct Answer:
1, 1, 1 2, 2, 2 3, 3, 3 3, 4, 4
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Arrays
What will be the output of the program if the array begins at address 65486? #include
int main() { int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u\n", arr, &arr); return 0; }
What will be the output of the program? #include
int main() { static int a[2][2] = {1, 2, 3, 4}; int i, j; static int *p[] = {(int*)a, (int*)a+1, (int*)a+2}; for(i=0; i<2; i++) { for(j=0; j<2; j++) { printf("%d, %d, %d, %d\n", *(*(p+i)+j), *(*(j+p)+i), *(*(i+p)+j), *(*(p+j)+i)); } } return 0; }
What will be the output of the program? #include
int main() { float arr[] = {12.4, 2.3, 4.5, 6.7}; printf("%d\n", sizeof(arr)/sizeof(arr[0])); return 0; }
What will be the output of the program? #include
int main() { void fun(int, int[]); int arr[] = {1, 2, 3, 4}; int i; fun(4, arr); for(i=0; i<4; i++) printf("%d,", arr[i]); return 0; } void fun(int n, int arr[]) { int *p=0; int i=0; while(i++ < n) p = &arr[i]; *p=0; }
What will be the output of the program in Turb C (under DOS)? #include
int main() { int arr[5], i=0; while(i<5) arr[i]=++i; for(i=0; i<5; i++) printf("%d, ", arr[i]); return 0; }
What will be the output of the program? #include
void fun(int **p); int main() { int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 8, 7, 8, 9, 0}; int *ptr; ptr = &a[0][0]; fun(&ptr); return 0; } void fun(int **p) { printf("%d\n", **p); }
What will be the output of the program if the array begins at 65472 and each integer occupies 2 bytes? #include
int main() { int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 1, 7, 8, 9, 0}; printf("%u, %u\n", a+1, &a+1); return 0; }
What will be the output of the program if the array begins 1200 in memory? #include
int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u\n", arr, &arr[0], &arr); return 0; }
What will be the output of the program? #include
int main() { int a[5] = {5, 1, 15, 20, 25}; int i, j, m; i = ++a[1]; j = a[1]++; m = a[i++]; printf("%d, %d, %d", i, j, m); return 0; }
What will be the output of the program? #include
int main() { int arr[1]={10}; printf("%d\n", 0[arr]); return 0; }
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