Will the program compile successfully? #include<stdio.h> #define X (4+Y) #define

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Question

Will the program compile successfully?

#include<stdio.h>
#define X (4+Y)
#define Y (X+3)

int main()
{
    printf("%d\n", 4*X+2);
    return 0;
}

Options
A. Yes
B. No

Correct Answer

No

Explanation

Reports an error: Undefined symbol 'X'

More questions

1. Bitwise | can be used to set a bit in number.
Options
A. Yes
B. No

Discuss

Correct Answer: Yes

2. Can we have an array of bit fields?
Options
A. Yes
B. No

Discuss

Correct Answer: No

3. By default structure variable will be of auto storage class
Options
A. Yes
B. No

Discuss

Correct Answer: Yes

4. Bitwise can be used to reverse a sign of a number.
Options
A. Yes
B. No

Discuss

Correct Answer: No

5. Is it necessary that in a function which accepts variable argument list there should be at least be one fixed argument?
Options
A. Yes
B. No

Discuss

Correct Answer: Yes

6. Bitwise can be used to generate a random number.
Options
A. Yes
B. No

Discuss

Correct Answer: No

7. A function that receives variable number of arguments should use va_arg() to extract the last argument from the variable argument list.
Options
A. True
B. False

Discuss

Correct Answer: False

8. Bitwise & can be used to check if more than one bit in a number is on.
Options
A. True
B. False

Discuss

Correct Answer: True

9. The preprocessor can trap simple errors like missing declarations, nested comments or mismatch of braces.
Options
A. True
B. False

Discuss

Correct Answer: False

Explanation:

False, the preprocessor cannot trap the errors, it only replaces the macro with the given expression. But the compiler will detect errors.

10. It is necessary that a header files should have a .h extension?
Options
A. Yes
B. No

Discuss

Correct Answer: No

Explanation:

No, the header files have any kind of extension.

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Will the program compile successfully?
#include<stdio.h> #define X (4+Y) #define Y (X+3) int main() { printf("%d\n", 4*X+2); return 0; }

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Will the program compile successfully? #include<stdio.h> #define X (4+Y) #define Y (X+3) int main() { printf("%d\n", 4*X+2); return 0; }

More questions

More in C Programming:

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Will the program compile successfully?
#include<stdio.h> #define X (4+Y) #define Y (X+3) int main() { printf("%d\n", 4*X+2); return 0; }