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  • Question
  • What will be the output of the program?
    #include<stdio.h>
    #define MAX(a, b) (a > b? a : b)
    
    int main()
    {
        int x;
        x = MAX(3+2, 2+7);
        printf("%d\n", x);
        return 0;
    }
    


  • Options
  • A. 8
  • B. 9
  • C. 6
  • D. 5

  • Correct Answer


  • Explanation
    The macro MAX(a, b) (a > b ? a : b) returns the biggest value of the given two numbers.

    Step 1 : int x; The variable x is declared as an integer type.

    Step 2 : x = MAX(3+2, 2+7); becomes,

    => x = (3+2 > 2+7 ? 3+2 : 2+7)

    => x = (5 > 9 ? 5 : 9)

    => x = 9

    Step 3 : printf("%d\n", x); It prints the value of variable x.

    Hence the output of the program is 9.


    More questions

    • 1. Assuming, integer is 2 byte, What will be the output of the program?
      #include;
      
      int main()
      {
          printf("%x\n", -1>>1);
          return 0;
      }
      

    • Options
    • A. ffff
    • B. 0fff
    • C. 0000
    • D. fff0
    • Discuss
    • 2. What is the output of the program given below?
      #include<stdio.h>
      int main()
      {
          enum status { pass, fail, atkt};
          enum status stud1, stud2, stud3;
          stud1 = pass;
          stud2 = atkt;
          stud3 = fail;
          printf("%d, %d, %d\n", stud1, stud2, stud3);
          return 0;
      }
      

    • Options
    • A. 0, 1, 2
    • B. 1, 2, 3
    • C. 0, 2, 1
    • D. 1, 3, 2
    • Discuss
    • 3. What will be the output of the program?
      #include<stdio.h>
      int main()
      {
          char ch;
          ch = 'A';
          printf("The letter is");
          printf("%c", ch >= 'A' && ch <= 'Z'? ch + 'a' - 'A':ch);
          printf("Now the letter is");
          printf("%c\n", ch >= 'A' && ch <= 'Z'? ch : ch + 'a' - 'A');
          return 0;
      }
      

    • Options
    • A. The letter is a
      Now the letter is A
    • B. The letter is A
      Now the letter is a
    • C. Error
    • D. None of above
    • Discuss
    • 4. What will be the output of the program?
      #include<stdio.h>
      int main()
      {
          int k, num=30;
          k = (num>5? (num <=10? 100 : 200): 500);
          printf("%d\n", num);
          return 0;
      }
      

    • Options
    • A. 200
    • B. 30
    • C. 100
    • D. 500
    • Discuss
    • 5. If a function contains two return statements successively, the compiler will generate warnings. Yes/No?

    • Options
    • A. Yes
    • B. No
    • Discuss
    • 6. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          char *str;
          str = "%s";
          printf(str, "K\n");
          return 0;
      }
      

    • Options
    • A. Error
    • B. No output
    • C. K
    • D. %s
    • Discuss
    • 7. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          char str1[] = "India";
          char str2[] = "CURIOUSTAB";
          char *s1 = str1, *s2=str2;
          while(*s1++ = *s2++)
              printf("%s", str1);
      
          printf("\n");
          return 0;
      }
      

    • Options
    • A. CuriousTab
    • B. BndiaBIdiaCURIOUSTABia
    • C. India
    • D. (null)
    • Discuss
    • 8. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          int x=30, *y, *z;
          y=&x; /* Assume address of x is 500 and integer is 4 byte size */
          z=y;
          *y++=*z++;
          x++;
          printf("x=%d, y=%d, z=%d\n", x, y, z);
          return 0;
      }
      

    • Options
    • A. x=31, y=502, z=502
    • B. x=31, y=500, z=500
    • C. x=31, y=498, z=498
    • D. x=31, y=504, z=504
    • Discuss
    • 9. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          char *p;
          p="hello";
          printf("%s\n", *&*&p);
          return 0;
      }
      

    • Options
    • A. llo
    • B. hello
    • C. ello
    • D. h
    • Discuss
    • 10. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          int i=3, *j, k;
          j = &i;
          printf("%d\n", i**j*i+*j);
          return 0;
      }
      

    • Options
    • A. 30
    • B. 27
    • C. 9
    • D. 3
    • Discuss


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