What will be the output of the program?

#include<stdio.h>
#define FUN(arg) do\
                 {\
                    if(arg)\
                        printf("CuriousTab...", "\n");\
                  }while(--i)

int main()
{
    int i=2;
    FUN(i<3);
    return 0;
}

Step 1: int i=2; The variable i is declared as an integer type and initialized to 2.

Step 2: FUN(i<3); becomes,

do
{
    if(2 < 3)
    printf("CuriousTab...", "\n");
}while(--2)

After the 2 while loops the value of i becomes '0'(zero). Hence the while loop breaks.

Hence the output of the program is "CuriousTab... CuriousTab..."