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- Question
What will be the output of the program?
#include<stdio.h> #define MESS junk int main() { printf("MESS\n"); return 0; }
Options- A. junk
- B. MESS
- C. Error
- D. Nothing will print
- Correct Answer
- MESS
Explanationprintf("MESS\n"); It prints the text "MESS". There is no macro calling inside the printf statement occured.
More questions
- 1. Macros have a local scope.
Options- A. True
- B. False Discuss
Correct Answer: False
Explanation:
False, The scope of macros is globals and functions. Also the scope of macros is only from the point of definition to the end of the file.- 2. If an unsigned int is 2 bytes wide then, What will be the output of the program?
#include<stdio.h> int main() { unsigned int a=0xffff; ~a; printf("%x\n", a); return 0; }
Options- A. ffff
- B. 0000
- C. 00ff
- D. ddfd Discuss
Correct Answer: ffff
- 3. Declare the following statement?
"A pointer to an array of three chars".
Options- A.
char *ptr[3](); - B.
char (*ptr)*[3]; - C.
char (*ptr[3])(); - D.
char (*ptr)[3];
Discuss
Correct Answer:char (*ptr)[3];
- 4. What will be the output of the program?
#include<stdio.h> int main() { unsigned int res; res = (64 >>(2+1-2)) & (~(1<<2)); printf("%d\n", res); return 0; }
Options- A. 32
- B. 64
- C. 0
- D. 128 Discuss
Correct Answer: 32
- 5. Union elements can be of different sizes.
Options- A. True
- B. False Discuss
Correct Answer: True
- 6. What will be the output of the program in DOS (Compiler - Turbo C)?
#include<stdio.h> double i; int main() { (int)(float)(char) i; printf("%d",sizeof(i)); return 0; }
Options- A. 4
- B. 8
- C. 16
- D. 22 Discuss
Correct Answer: 8
- 7. size of union is size of the longest element in the union
Options- A. Yes
- B. No Discuss
Correct Answer: Yes
- 8. Bitwise & can be used to divide a number by powers of 2
Options- A. True
- B. False Discuss
Correct Answer: False
- 9. Assuming, integer is 2 byte, What will be the output of the program?
#include
; int main() { printf("%x\n", -1>>1); return 0; }
Options- A. ffff
- B. 0fff
- C. 0000
- D. fff0 Discuss
Correct Answer: ffff
Explanation:
Negative numbers are treated with 2's complement method.
1's complement: Inverting the bits ( all 1s to 0s and all 0s to 1s)
2's complement: Adding 1 to the result of 1's complement.
Binary of 1(2byte) : 0000 0000 0000 0001 Representing -1: 1s complement of 1(2byte) : 1111 1111 1111 1110 Adding 1 to 1's comp. result : 1111 1111 1111 1111 Right shift 1bit(-1>>1): 1111 1111 1111 1111 (carry out 1) Hexadecimal : f f f f (Filled with 1s in the left side in the above step)
Note:1. Fill with 1s in the left side for right shift for negative numbers.
2. Fill with 0s in the right side for left shift for negative numbers.
3. Fill with 0s in the left side for right shift for positive numbers.
4. Fill with 0s in the right side for left shift for positive numbers.- 10. What is the output of the program given below?
#include<stdio.h> int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, stud3); return 0; }
Options- A. 0, 1, 2
- B. 1, 2, 3
- C. 0, 2, 1
- D. 1, 3, 2 Discuss
Correct Answer: 0, 2, 1
Explanation:
enum takes the format like {0,1,2..) so pass=0, fail=1, atkt=2stud1 = pass (value is 0)
stud2 = atkt (value is 2)
stud3 = fail (value is 1)
Hence it prints 0, 2, 1
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