1: | Every if-else statement can be replaced by an equivalent statements using ?: operators |
2: | Nested if-else statements are allowed. |
3: | Multiple statements in an if block are allowed. |
4: | Multiple statements in an else block are allowed. |
#include<stdio.h> int main() { struct bits { int i:40; }bit; printf("%d\n", sizeof(bit)); return 0; }
#include<stdio.h> #include<stdarg.h> int main() { void display(int num, ...); display(4, 12.5, 13.5, 14.5, 44.3); return 0; } void display(int num, ...) { float c; int j; va_list ptr; va_start(ptr, num); for(j=1; j<=num; j++) { c = va_arg(ptr, float); printf("%f", c); } }
/* sample.c */ #include<stdio.h> int main(int argc, char *argv[]) { int j; j = argv[1] + argv[2] + argv[3]; printf("%d", j); return 0; }
Example: j = atoi(argv[1]) + atoi(argv[2]) + atoi(argv[3]);
#include<stdio.h> int main() { float a=3.14; char *j; j = (char*)&a; printf("%d\n", *j); return 0; }
#include<stdio.h> int main() { int i=4; switch(i) { default: printf("This is default\n"); case 1: printf("This is case 1\n"); break; case 2: printf("This is case 2\n"); break; case 3: printf("This is case 3\n"); } return 0; }
In default statement there is no break; statement is included. So it prints the case 1 statements. "This is case 1".
Then the break; statement is encountered. Hence the program exits from the switch-case block.
#include<stdio.h> int main() { int a = 300, b, c; if(a >= 400) b = 300; c = 200; printf("%d, %d, %d\n", a, b, c); return 0; }
#include<stdio.h> int main() { int x = 10, y = 20; if(!(!x) && x) printf("x = %d\n", x); else printf("y = %d\n", y); return 0; }
Step 1: if(!(!x) && x)
Step 2: if(!(!10) && 10)
Step 3: if(!(0) && 10)
Step 3: if(1 && 10)
Step 4: if(TRUE) here the if condition is satisfied. Hence it prints x = 10.
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