What will be the output of the program?

#include<stdio.h>
int main()
{
    int a=0, b=1, c=3;
    *((a)? &b : &a) = a? b : c;
    printf("%d, %d, %d\n", a, b, c);
    return 0;
}

Step 2: *((a) ? &b : &a) = a ? b : c; The right side of the expression(a?b:c) becomes (0?1:3). Hence it return the value '3'.

The left side of the expression *((a) ? &b : &a) becomes *((0) ? &b : &a). Hence this contains the address of the variable a *(&a).

Step 3: *((a) ? &b : &a) = a ? b : c; Finally this statement becomes *(&a)=3. Hence the variable a has the value '3'.

Step 4: printf("%d, %d, %d\n", a, b, c); It prints "3, 1, 3".