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  • Question
  • What will be the output of the program?
    #include<stdio.h>
    int main()
    {
        unsigned int i = 65535; /* Assume 2 byte integer*/
        while(i++ != 0)
            printf("%d",++i);
        printf("\n");
        return 0;
    }
    


  • Options
  • A. Infinite loop
  • B. 0 1 2 ... 65535
  • C. 0 1 2 ... 32767 - 32766 -32765 -1 0
  • D. No output

  • Correct Answer
  • Infinite loop 

    Explanation
    Here unsigned int size is 2 bytes. It varies from 0,1,2,3, ... to 65535.

    Step 1:unsigned int i = 65535;

    Step 2:
    Loop 1: while(i++ != 0) this statement becomes while(65535 != 0). Hence the while(TRUE) condition is satisfied. Then the printf("%d", ++i); prints '1'(variable 'i' is already incremented by '1' in while statement and now incremented by '1' in printf statement) Loop 2: while(i++ != 0) this statement becomes while(1 != 0). Hence the while(TRUE) condition is satisfied. Then the printf("%d", ++i); prints '3'(variable 'i' is already incremented by '1' in while statement and now incremented by '1' in printf statement)
    ....
    ....

    The while loop will never stops executing, because variable i will never become '0'(zero). Hence it is an 'Infinite loop'.


    More questions

    • 1. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          char far *near *ptr1;
          char far *far *ptr2;
          char far *huge *ptr3;
          printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
          return 0;
      }
      

    • Options
    • A. 4, 4, 8
    • B. 4, 4, 4
    • C. 2, 4, 4
    • D. 2, 4, 8
    • Discuss
    • 2. Nested unions are allowed

    • Options
    • A. True
    • B. False
    • Discuss
    • 3. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          char huge *near *far *ptr1;
          char near *far *huge *ptr2;
          char far *huge *near *ptr3;
          printf("%d, %d, %d\n", sizeof(ptr1), sizeof(*ptr2), sizeof(**ptr3));
          return 0;
      }
      

    • Options
    • A. 4, 4, 4
    • B. 2, 4, 4
    • C. 4, 4, 2
    • D. 2, 4, 8
    • Discuss
    • 4. What will be the output of the program?
      #include<stdio.h>
      typedef void v;
      typedef int i;
      
      int main()
      {
          v fun(i, i);
          fun(2, 3);
          return 0;
      }
      v fun(i a, i b)
      {
          i s=2;
          float i;
          printf("%d,", sizeof(i));
          printf(" %d", a*b*s);
      }
      

    • Options
    • A. 2, 8
    • B. 4, 8
    • C. 2, 4
    • D. 4, 12
    • Discuss
    • 5. What will be the output of the program (myprog.c) given below if it is executed from the command line?
      cmd> myprog 1 2 3
      /* myprog.c */
      #include<stdio.h>
      #include<stdlib.h>
      
      int main(int argc, char **argv)
      {
          int i, j=0;
          for(i=0; i<argc; i++)
              j = j+atoi(argv[i]);
          printf("%d\n", j);
          return 0;
      }
      

    • Options
    • A. 123
    • B. 6
    • C. Error
    • D. "123"
    • Discuss
    • 6. What will be the output of the program in DOS (Compiler - Turbo C)?
      #include<stdio.h>
      double i;
      
      int main()
      {
          (int)(float)(char) i;
          printf("%d", sizeof((int)(float)(char)i));
          return 0;
      }
      

    • Options
    • A. 1
    • B. 2
    • C. 4
    • D. 8
    • Discuss
    • 7. Which files will get closed through the fclose() in the following program?
      #include<stdio.h>
      
      int main()
      {
          FILE *fs, *ft, *fp;
          fp = fopen("A.C", "r");
          fs = fopen("B.C", "r");
          ft = fopen("C.C", "r");
          fclose(fp, fs, ft);
          return 0;
      }
      

    • Options
    • A. "A.C" "B.C" "C.C"
    • B. "B.C" "C.C"
    • C. "A.C"
    • D. Error in fclose()
    • Discuss
    • 8. Which of the following are unary operators in C?

      1. !
      2. sizeof
      3. ~
      4. &&

    • Options
    • A. 1, 2
    • B. 1, 3
    • C. 2, 4
    • D. 1, 2, 3
    • Discuss
    • 9. Point out the error in the following program.
      #include<stdio.h>
      #include<stdarg.h>
      void varfun(int n, ...);
      
      int main()
      {
          varfun(3, 7, -11.2, 0.66);
          return 0;
      }
      void varfun(int n, ...)
      {
          float *ptr;
          int num;
          va_start(ptr, n);
          num = va_arg(ptr, int);
          printf("%d", num);
      }
      

    • Options
    • A. Error: too many parameters
    • B. Error: invalid access to list member
    • C. Error: ptr must be type of va_list
    • D. No error
    • Discuss
    • 10. Macros with arguments are allowed

    • Options
    • A. True
    • B. False
    • Discuss


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