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Home C Programming Constants See What Others Are Saying!
  • Question
  • Point out the error in the program (in Turbo-C).
    #include<stdio.h>
    #define MAX 128
    
    int main()
    {
        const int max=128;
        char array[max];
        char string[MAX];
        array[0] = string[0] = 'A';
        printf("%c %c\n", array[0], string[0]);
        return 0;
    }
    


  • Options
  • A. Error: unknown max in declaration/Constant expression required
  • B. Error: invalid array string
  • C. None of above
  • D. No error. It prints A A

  • Correct Answer
  • Error: unknown max in declaration/Constant expression required 

    Explanation
    Step 1: A macro named MAX is defined with value 128

    Step 2: const int max=128; The constant variable max is declared as an integer data type and it is initialized with value 128.

    Step 3: char array[max]; This statement reports an error "constant expression required". Because, we cannot use variable to define the size of array.

    To avoid this error, we have to declare the size of an array as static. Eg. char array[10]; or use macro char array[MAX];

    Note: The above program will print A A as output in Unix platform.


    More questions

    • 1. Which of the following statements correct about k used in the below statement?
      char ****k;

    • Options
    • A. k is a pointer to a pointer to a pointer to a char
    • B. k is a pointer to a pointer to a pointer to a pointer to a char
    • C. k is a pointer to a char pointer
    • D. k is a pointer to a pointer to a char
    • Discuss
    • 2. What will be the output of the program?
      #include<stdio.h>
      
      void fun(void *p);
      int i;
      
      int main()
      {
          void *vptr;
          vptr = &i;
          fun(vptr);
          return 0;
      }
      void fun(void *p)
      {
          int **q;
          q = (int**)&p;
          printf("%d\n", **q);
      }
      

    • Options
    • A. Error: cannot convert from void** to int**
    • B. Garbage value
    • C. 0
    • D. No output
    • Discuss
    • 3. What will be the output of the program?
      #include<stdio.h>
      #include<string.h>
      
      int main()
      {
          static char s[] = "Hello!";
          printf("%d\n", *(s+strlen(s)));
          return 0;
      }
      

    • Options
    • A. 8
    • B. 0
    • C. 16
    • D. Error
    • Discuss
    • 4. What will be the output of the program?
      #include<stdio.h>
      
      int main()
      {
          int i=4, j=8;
          printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j);
          return 0;
      }
      

    • Options
    • A. 4, 8, 0
    • B. 1, 2, 1
    • C. 12, 1, 12
    • D. 0, 0, 0
    • Discuss
    • 5. What will you do to treat the constant 3.14 as a float?

    • Options
    • A. use float(3.14f)
    • B. use 3.14f
    • C. use f(3.14)
    • D. use (f)(3.14)
    • Discuss
    • 6. What will be the output of the program if value 25 given to scanf()?
      #include<stdio.h>
      
      int main()
      {
          int i;
          printf("%d\n", scanf("%d", &i));
          return 0;
      }
      

    • Options
    • A. 25
    • B. 2
    • C. 1
    • D. 5
    • Discuss
    • 7. In the statement expression1 >> expression2. if expression1 is a signed integer with its leftmost bit set to 1 then on right shifting it the result of the statement will vary from computer to computer

    • Options
    • A. True
    • B. False
    • Discuss
    • 8. What do the following declaration signify?
      int *ptr[30];

    • Options
    • A. ptr is a pointer to an array of 30 integer pointers.
    • B. ptr is a array of 30 pointers to integers.
    • C. ptr is a array of 30 integer pointers.
    • D. ptr is a array 30 pointers.
    • Discuss
    • 9. Range of float id -2.25e+308 to 2.25e+308

    • Options
    • A. True
    • B. False
    • Discuss
    • 10. What will be the output of the program (in Turbo C under DOS)?
      #include<stdio.h>
      
      int main()
      {
          char huge *near *far *ptr1;
          char near *far *huge *ptr2;
          char far *huge *near *ptr3;
          printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
          return 0;
      }
      

    • Options
    • A. 4, 4, 8
    • B. 2, 4, 4
    • C. 4, 4, 2
    • D. 2, 4, 8
    • Discuss


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