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- Question
What will be the output of the program?
#include<stdio.h> int main() { printf("%c\n", ~('C'*-1)); return 0; }
Options- A. A
- B. B
- C. C
- D. D
- Correct Answer
- B
- 1. What will be the output of the program?
#include<stdio.h> int main() { FILE *fp; unsigned char ch; /* file 'abc.c' contains "This is CuriousTab " */ fp=fopen("abc.c", "r"); if(fp == NULL) { printf("Unable to open file"); exit(1); } while((ch=getc(fp)) != EOF) printf("%c", ch); fclose(fp); printf("\n", ch); return 0; }
Options- A. This is CuriousTab
- B. This is
- C. Infinite loop
- D. Error Discuss
- 2. What will be the output of the program if value 25 given to scanf()?
#include<stdio.h> int main() { int i; printf("%d\n", scanf("%d", &i)); return 0; }
Options- A. 25
- B. 2
- C. 1
- D. 5 Discuss
- 3. What will be the output of the program?
#include<stdio.h> int main() { FILE *fp; char ch, str[7]; fp=fopen("try.c", "r"); /* file 'try.c' contains "This is Nagpur" */ fseek(fp, 9L, SEEK_CUR); fgets(str, 5, fp); puts(str); return 0; }
Options- A. agpur
- B. gpur
- C. Nagp
- D. agpu Discuss
- 4. What will be the output of the program?
#include<stdio.h> int main() { int a=250; printf("%1d \n", a); return 0; }
Options- A. 1250
- B. 2
- C. 50
- D. 250 Discuss
- 5. What will be the output of the program?
#include<stdio.h> int main() { float a=3.15529; printf("%2.1f\n", a); return 0; }
Options- A. 3.00
- B. 3.15
- C. 3.2
- D. 3 Discuss
- 6. What will be the output of the program?
#include<stdio.h> int main() { char *p; p="%d\n"; p++; p++; printf(p-2, 23); return 0; }
Options- A. 21
- B. 23
- C. Error
- D. No output Discuss
- 7. If the file 'source.txt' contains a line "Be my friend" which of the following will be the output of below program?
#include<stdio.h> int main() { FILE *fs, *ft; char c[10]; fs = fopen("source.txt", "r"); c[0] = getc(fs); fseek(fs, 0, SEEK_END); fseek(fs, -3L, SEEK_CUR); fgets(c, 5, fs); puts(c); return 0; }
Options- A. friend
- B. frien
- C. end
- D. Error in fseek(); Discuss
- 8. What will be the output of the program?
#include<stdio.h> char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; int main() { printf(str, 34, str, 34); return 0; }
Options- A. char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; main(){ printf(str, 34, str, 34);}
- B. char *str = %c%s%c; main(){ printf(str, 34, str, 34);}
- C. No output
- D. Error in program Discuss
- 9. What will be the output of the program?
#include<stdio.h> int main() { printf("%%%%\n"); return 0; }
Options- A. %%%%%
- B. %%
- C. No output
- D. Error Discuss
- 10. Assuming, integer is 2 byte, What will be the output of the program?
#include
; int main() { printf("%x\n", -1>>1); return 0; }
Options- A. ffff
- B. 0fff
- C. 0000
- D. fff0 Discuss
Input / Output problems
Search Results
Correct Answer: Infinite loop
Explanation:
while((ch=getc(fp)) != EOF) Here getc function read the character and convert it to an integer value and store it in the variable ch, but it is declared as an unsigned char. So the while loop runs infinitely.
Correct Answer: 1
Explanation:
printf("%d\n", scanf("%d", &i)); The scanf function returns the value 1(one).
Therefore, the output of the program is '1'.
Correct Answer: agpu
Correct Answer: 250
Explanation:
printf("%1d \n", a); It prints the value of variable a.
Hence the output of the program is 250.
Correct Answer: 3.2
Explanation:
printf("%2.1f\n", a); The precision specifier tells .1f tells the printf function to place only one number after the .(dot).
Hence the output is 3.2
Correct Answer: 23
Correct Answer: end
Explanation:
fseek(fs, 0, SEEK_END); moves the file pointer to the end of the file.
fseek(fs, -3L, SEEK_CUR); moves the file pointer backward by 3 characters.
fgets(c, 5, fs); read the file from the current position of the file pointer.
Hence, it contains the last 3 characters of "Be my friend".
Therefore, it prints "end".
Correct Answer: char *str = "char *str = %c%s%c; main(){ printf(str, 34, str, 34);}"; main(){ printf(str, 34, str, 34);}
Correct Answer: %%
Correct Answer: ffff
Explanation:
1's complement: Inverting the bits ( all 1s to 0s and all 0s to 1s)
2's complement: Adding 1 to the result of 1's complement.
Binary of 1(2byte) : 0000 0000 0000 0001 Representing -1: 1s complement of 1(2byte) : 1111 1111 1111 1110 Adding 1 to 1's comp. result : 1111 1111 1111 1111 Right shift 1bit(-1>>1): 1111 1111 1111 1111 (carry out 1) Hexadecimal : f f f f (Filled with 1s in the left side in the above step)Note:
1. Fill with 1s in the left side for right shift for negative numbers.
2. Fill with 0s in the right side for left shift for negative numbers.
3. Fill with 0s in the left side for right shift for positive numbers.
4. Fill with 0s in the right side for left shift for positive numbers.
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