Discussion
Home ‣ C Programming ‣ Functions Comments
- Question
What will be the output of the program?
#include<stdio.h> int check(int); int main() { int i=45, c; c = check(i); printf("%d\n", c); return 0; } int check(int ch) { if(ch >= 45) return 100; else return 10; }
Options- A. 100
- B. 10
- C. 1
- D. 0
- Correct Answer
- 100
ExplanationStep 1: int check(int); This prototype tells the compiler that the function check() accepts one integer parameter and returns an integer value.Step 2: int l=45, c; The variable i and c are declared as an integer type and i is initialized to 45.
The function check(i) return 100 if the given value of variable i is >=(greater than or equal to) 45, else it will return 10.
Step 3: c = check(i); becomes c = check(45); The function check() return 100 and it get stored in the variable c.(c = 100)
Step 4: printf("%d\n", c); It prints the value of variable c.
Hence the output of the program is '100'.
Functions problems
Search Results
- 1. What will be the output of the program?
#include<stdio.h> int check (int, int); int main() { int c; c = check(10, 20); printf("c=%d\n", c); return 0; } int check(int i, int j) { int *p, *q; p=&i; q=&j; i>=45? return(*p): return(*q); }
Options- A. Print 10
- B. Print 20
- C. Print 1
- D. Compile error Discuss
Correct Answer: Compile error
Explanation:
There is an error in this line i>=45 ? return(*p): return(*q);. We cannot use return keyword in the terenary operators.- 2. What will be the output of the program?
#include<stdio.h> void fun(int); typedef int (*pf) (int, int); int proc(pf, int, int); int main() { int a=3; fun(a); return 0; } void fun(int n) { if(n > 0) { fun(--n); printf("%d,", n); fun(--n); } }
Options- A. 0, 2, 1, 0,
- B. 1, 1, 2, 0,
- C. 0, 1, 0, 2,
- D. 0, 1, 2, 0, Discuss
Correct Answer: 0, 1, 2, 0,
- 3. What will be the output of the program?
#include<stdio.h> int fun(int); int main() { float k=3; fun(k=fun(fun(k))); printf("%f\n", k); return 0; } int fun(int i) { i++; return i; }
Options- A. 5.000000
- B. 3.000000
- C. Garbage value
- D. 4.000000 Discuss
Correct Answer: 5.000000
- 4. What will be the output of the program?
#include<stdio.h> int reverse(int); int main() { int no=5; reverse(no); return 0; } int reverse(int no) { if(no == 0) return 0; else printf("%d,", no); reverse (no--); }
Options- A. Print 5, 4, 3, 2, 1
- B. Print 1, 2, 3, 4, 5
- C. Print 5, 4, 3, 2, 1, 0
- D. Infinite loop Discuss
Correct Answer: Infinite loop
Explanation:
Step 1: int no=5; The variable no is declared as integer type and initialized to 5.Step 2: reverse(no); becomes reverse(5); It calls the function reverse() with '5' as parameter.
The function reverse accept an integer number 5 and it returns '0'(zero) if(5 == 0) if the given number is '0'(zero) or else printf("%d,", no); it prints that number 5 and calls the function reverse(5);.
The function runs infinetely because the there is a post-decrement operator is used. It will not decrease the value of 'n' before calling the reverse() function. So, it calls reverse(5) infinitely.
Note: If we use pre-decrement operator like reverse(--n), then the output will be 5, 4, 3, 2, 1. Because before calling the function, it decrements the value of 'n'.
- 5. What will be the output of the program?
#include<stdio.h> int main() { int fun(int); int i = fun(10); printf("%d\n", --i); return 0; } int fun(int i) { return (i++); }
Options- A. 9
- B. 10
- C. 11
- D. 8 Discuss
Correct Answer: 9
Explanation:
Step 1: int fun(int); Here we declare the prototype of the function fun().Step 2: int i = fun(10); The variable i is declared as an integer type and the result of the fun(10) will be stored in the variable i.
Step 3: int fun(int i){ return (i++); } Inside the fun() we are returning a value return(i++). It returns 10. because i++ is the post-increement operator.
Step 4: Then the control back to the main function and the value 10 is assigned to variable i.
Step 5: printf("%d\n", --i); Here --i denoted pre-increement. Hence it prints the value 9.
- 6. What will be the output of the program?
#include<stdio.h> #include<stdlib.h> int main() { int i=0; i++; if(i<=5) { printf("CuriousTab"); exit(1); main(); } return 0; }
Options- A. Prints "CuriousTab" 5 times
- B. Function main() doesn't calls itself
- C. Infinite loop
- D. Prints "CuriousTab" Discuss
Correct Answer: Prints "CuriousTab"
Explanation:
Step 1: int i=0; The variable i is declared as in integer type and initialized to '0'(zero).Step 2: i++; Here variable i is increemented by 1. Hence i becomes '1'(one).
Step 3: if(i<=5) becomes if(1 <=5). Hence the if condition is satisfied and it enter into if block statements.
Step 4: printf("CuriousTab"); It prints "CuriousTab".
Step 5: exit(1); This exit statement terminates the program execution.
Hence the output is "CuriousTab".
- 7. In C all functions except main() can be called recursively.
Options- A. True
- B. False Discuss
Correct Answer: False
Explanation:
Any function including main() can be called recursively.- 8. Functions cannot return more than one value at a time
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
True, A function cannot return more than one value at a time. because after returning a value the control is given back to calling function.- 9. A function cannot be defined inside another function
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
A function cannot be defined inside the another function, but a function can be called inside a another function.- 10. If return type for a function is not specified, it defaults to int
Options- A. True
- B. False Discuss
Correct Answer: True
Explanation:
True, The default return type for a function is int.
Comments
There are no comments.
More in C Programming:
Programming
Copyright ©CuriousTab. All rights reserved.
- 1. What will be the output of the program?