What will be the output of the program?

#include<stdio.h>
int check(int);
int main()
{
    int i=45, c;
    c = check(i);
    printf("%d\n", c);
    return 0;
}
int check(int ch)
{
    if(ch >= 45)
        return 100;
    else
        return 10;
}

Step 2: int l=45, c; The variable i and c are declared as an integer type and i is initialized to 45.

The function check(i) return 100 if the given value of variable i is >=(greater than or equal to) 45, else it will return 10.

Step 3: c = check(i); becomes c = check(45); The function check() return 100 and it get stored in the variable c.(c = 100)

Step 4: printf("%d\n", c); It prints the value of variable c.

Hence the output of the program is '100'.