= 45) "> = 45) ">
#include<stdio.h> int check(int); int main() { int i=45, c; c = check(i); printf("%d\n", c); return 0; } int check(int ch) { if(ch >= 45) return 100; else return 10; }
Step 2: int l=45, c; The variable i and c are declared as an integer type and i is initialized to 45.
The function check(i) return 100 if the given value of variable i is >=(greater than or equal to) 45, else it will return 10.
Step 3: c = check(i); becomes c = check(45); The function check() return 100 and it get stored in the variable c.(c = 100)
Step 4: printf("%d\n", c); It prints the value of variable c.
Hence the output of the program is '100'.
#include<stdio.h> void fun(void *p); int i; int main() { void *vptr; vptr = &i; fun(vptr); return 0; } void fun(void *p) { int **q; q = (int**)&p; printf("%d\n", **q); }
#include<stdio.h> #include<string.h> int main() { static char s[] = "Hello!"; printf("%d\n", *(s+strlen(s))); return 0; }
#include<stdio.h> int main() { int i=4, j=8; printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j); return 0; }
#include<stdio.h> int main() { int i; printf("%d\n", scanf("%d", &i)); return 0; }
printf("%d\n", scanf("%d", &i)); The scanf function returns the value 1(one).
Therefore, the output of the program is '1'.
int *ptr[30];
#include<stdio.h> int main() { char huge *near *far *ptr1; char near *far *huge *ptr2; char far *huge *near *ptr3; printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3)); return 0; }
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