Assuming, integer is 2 byte, What will be the output of the program?

#include<stdio.h>

int main()
{
    printf("%x\n", -2<<2);
    return 0;
}

#include<stdio.h>
int main()
{
    enum status { pass, fail, atkt};
    enum status stud1, stud2, stud3;
    stud1 = pass;
    stud2 = atkt;
    stud3 = fail;
    printf("%d, %d, %d\n", stud1, stud2, stud3);
    return 0;
}

#include<stdio.h>
int main()
{
    char ch;
    ch = 'A';
    printf("The letter is");
    printf("%c", ch >= 'A' && ch <= 'Z'? ch + 'a' - 'A':ch);
    printf("Now the letter is");
    printf("%c\n", ch >= 'A' && ch <= 'Z'? ch : ch + 'a' - 'A');
    return 0;
}

#include<stdio.h>
int main()
{
    int k, num=30;
    k = (num>5? (num <=10? 100 : 200): 500);
    printf("%d\n", num);
    return 0;
}

#include<stdio.h>

int main()
{
    char *str;
    str = "%s";
    printf(str, "K\n");
    return 0;
}

#include<stdio.h>

int main()
{
    char str1[] = "India";
    char str2[] = "CURIOUSTAB";
    char *s1 = str1, *s2=str2;
    while(*s1++ = *s2++)
        printf("%s", str1);

    printf("\n");
    return 0;
}

#include<stdio.h>

int main()
{
    int x=30, *y, *z;
    y=&x; /* Assume address of x is 500 and integer is 4 byte size */
    z=y;
    *y++=*z++;
    x++;
    printf("x=%d, y=%d, z=%d\n", x, y, z);
    return 0;
}

#include<stdio.h>

int main()
{
    char *p;
    p="hello";
    printf("%s\n", *&*&p);
    return 0;
}

#include<stdio.h>

int main()
{
    int i=3, *j, k;
    j = &i;
    printf("%d\n", i**j*i+*j);
    return 0;
}

#include<stdio.h>

int main()
{
    printf("%c\n", 7["CuriousTab"]);
    return 0;
}