#include<stdio.h> int main() { int i=5; for(;scanf("%s", &i); printf("%d\n", i)); return 0; }
Hence this for loop would get executed infinite times.
#include<stdio.h> int main() { extern int fun(float); int a; a = fun(3.14); printf("%d\n", a); return 0; } int fun(int aa) { return (int)++aa; }
#include<stdio.h> int X=40; int main() { int X=20; printf("%d\n", X); return 0; }
#include<stdio.h> int main() { extern int a; printf("%d\n", a); return 0; } int a=20;
printf("%d\n", a); it prints the value of local variable int a = 20. Because, whenever there is a conflict between local variable and global variable, local variable gets the highest priority. So it prints 20.
#include<stdio.h> int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, stud3); return 0; }
stud1 = pass (value is 0)
stud2 = atkt (value is 2)
stud3 = fail (value is 1)
Hence it prints 0, 2, 1
#include<stdio.h> int main() { extern int i; i = 20; printf("%d\n", sizeof(i)); return 0; }
#include<stdio.h> int main() { int a[5] = {2, 3}; printf("%d, %d, %d\n", a[2], a[3], a[4]); return 0; }
#include<stdio.h> int main() { char *s1; char far *s2; char huge *s3; printf("%d, %d, %d\n", sizeof(s1), sizeof(s2), sizeof(s3)); return 0; }
Since C is a compiler dependent language, it may give different output in other platforms. The above program works fine in Windows (TurboC), but error in Linux (GCC Compiler).
#include<stdio.h> int main() { int x = 10, y = 20, z = 5, i; i = x < y < z; printf("%d\n", i); return 0; }
#include<stdio.h> int main() { struct emp { char name[20]; int age; float sal; }; struct emp e = {"Tiger"}; printf("%d, %f\n", e.age, e.sal); return 0; }
#include<stdio.h> int main() { int X=40; { int X=20; printf("%d ", X); } printf("%d\n", X); return 0; }
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