Difficulty: Medium
Correct Answer: ASRA
Explanation:
Introduction / Context:
Reverse-assembling a machine opcode requires knowledge of the ISA’s opcode map. Single-byte opcodes typically encode accumulator/register operations or short addressing forms, whereas instructions with immediate or direct addresses need extra operand bytes.
Given Data / Assumptions:
Concept / Approach:
If the instruction consumed only one byte, it cannot encode the multi-byte immediates or addresses visible in options (b), (c), (d). Therefore, a unary accumulator operation such as ASRA (arithmetic shift right accumulator) is the consistent choice.
Step-by-Step Solution:
Check each option’s operand length.Options with h#.... operands require additional bytes and contradict the single 0x48 byte.Select the operand-less accumulator operation as the plausible decoding.
Verification / Alternative check:
Consulting the ISA manual would definitively map 0x48 to its mnemonic. In many classic ISAs, 0x48 corresponds to single-byte register/shift ops, aligning with ASRA over memory-addressing forms.
Why Other Options Are Wrong:
(b), (c), (d) each imply at least two additional operand bytes; they cannot be encoded by a lone 0x48. (e) likewise suggests addressing.
Common Pitfalls:
Ignoring instruction length; assuming any mnemonic can match without checking required operands.
Final Answer:
ASRA.
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