Face I -> a, Face IV -> b, Face III -> c, Face II -> d, Face V -> e, Face VI -> f
Therefore 'a' appears opposite 'c'.
Hence, when 'c' is at the top, then 'a' will be at the bottom.
Except figure (1) all others are irregular.
Figure (1) is a regular pentagon.So figure ( 1 ) is correct answer .
The number of projections doubles in each step.
Rest all are horizontal element except (e) which is vertical
Only two faces are coloured is when cubes are at the edges (baring the corner cubes)
If no cubes have been removed then on each edges we will get 3 cubes that has exactly 2 faces coloured, hence total number of such cubes = 12 x 3 = 36, because we have 12 edges.
Out of these 3 cubes are removed hence required number of cubes = 36 - 3 = 33
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