From figures (i), (iii) and (iv), we conclude that 4, 5, 6 and 1 lie adjacent to 3. Therefore, 2 must lie opposite 3. Now, we have 1 opposite 5 and 2 opposite 3. Hence, 4 must lie opposite 6.
Face I -> a, Face IV -> b, Face III -> c, Face II -> d, Face V -> e, Face VI -> f
Therefore 'a' appears opposite 'c'.
Hence, when 'c' is at the top, then 'a' will be at the bottom.
Since, these two faces are opposite to each other, therefore, two dots are contained on the face opposite to that containing four dots.
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