Group the given figures into three classes using each figure only once.

From first figure to second figure in the first unit of Problem Figures the shaded parts become white and vice-versa. The lower squares become rectangular in shape.

NA

NA

From first figure to second figure an inverted figure is also added.

All other figures have small mouth.But figure ( 2 ) has different to others .

On the basis of given figure in above question, we can say that
The square rotates through 45° clockwise while the white and the black dots move in anticlockwise direction (i.e., from left to right).
Hence , option C will come on the place of ? .

For least number of cuts 120 = 4 x 5 x 6 i.e number of cuts must be 3, 4 and 5 in three planes in this case number of cubes on a face is either 6 x 5 = 30 or 6 x 4 = 24 or 4 x 5 = 20 cubes . And number of cuboids on an edge is 4 or 5 or 6
Maximum number of cuboid with red colour is possible when cube is painted with red colour in 3 sides with minimum number of common edges (which is equal to 2)
Hence required maximum value is 6 (5 + 5 + 4 - 2) = 72
For minimum number of such cuboid Red colour is used only once and minimum number of cubes in that case is 20
Hence required ratio is 72 : 20 = 18 : 5

NA

Here on each face 6 x 6 = 36 cubes that are painted with one colour.
Case (i): when these three colour are adjacent to each other then from one face we will get 6 x 6 = 36 cubes but out them 6 x 3 = 18 cubes from common edge is common so number of cubes are 3 x 6 x 6 - 6 x 3 = 90
Case (ii): When red and blue are opposite to each other (or any two of the given three) then required number of cubes is 3 x 6 x 6 - 2 x 6 = 96