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  • Question
  • 3 × 101 + 7 × 100 is equal to ________.


  • Options
  • A. 3.7
  • B. 37
  • C. 10
  • D. 370

  • Correct Answer
  • 37 


  • Number Systems and Codes problems


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    • 1. Which of the following is the primary advantage of using the BCD code instead of straight binary coding?

    • Options
    • A. Fewer bits are required to represent a decimal number with the BCD code.
    • B. The relative ease of converting to and from decimal.
    • C. BCD codes are easily converted to hexadecimal codes.
    • D. BCD codes are easily converted to straight binary codes.
    • Discuss
    • 2. Convert binary 1001 to hexadecimal.

    • Options
    • A. 916
    • B. 1116
    • C. 10116
    • D. 1016
    • Discuss
    • 3. The sum of the two BCD numbers, 0011 + 0011, is ________.

    • Options
    • A. 0110
    • B. 0111
    • C. 0011
    • D. 1100
    • Discuss
    • 4. The sum of 11101 + 10111 equals ________.

    • Options
    • A. 110011
    • B. 100001
    • C. 110100
    • D. 100100
    • Discuss
    • 5. 3428 is the decimal value for which of the following binary-coded decimal (BCD) groupings?

    • Options
    • A. 11010001001000
    • B. 11010000101000
    • C. 011010010000010
    • D. 110100001101010
    • Discuss
    • 6. The 2's complement of 11100111 is ________.

    • Options
    • A. 11100110
    • B. 00011001
    • C. 00011000
    • D. 00011010
    • Discuss
    • 7. Convert hexadecimal value 16 to decimal.

    • Options
    • A. 2210
    • B. 1610
    • C. 1010
    • D. 2010
    • Discuss
    • 8. Select one of the following statements that best describes the parity method of error detection.

    • Options
    • A. Parity checking is best suited for detecting single-bit errors in transmitted codes.
    • B. Parity checking is not suitable for detecting single-bit errors in transmitted codes.
    • C. Parity checking is capable of detecting and correcting errors in transmitted codes.
    • D. Parity checking is best suited for detecting double-bit errors that occur during the transmission of codes from one location to another.
    • Discuss
    • 9. The binary number 101110101111010 can be written in octal as ________.

    • Options
    • A. 515628
    • B. 565778
    • C. 656278
    • D. 565728
    • Discuss
    • 10. What is the resultant binary of the decimal problem 49 + 01 =?

    • Options
    • A. 01010101
    • B. 00110101
    • C. 00110010
    • D. 00110001
    • Discuss


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