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- Question
For a 4-bit parallel adder, if the carry-in is connected to a logical HIGH, the result is:
Options- A. the same as if the carry-in is tied LOW since the least significant carry-in is ignored.
- B. that carry-out will always be HIGH.
- C. a one will be added to the final result.
- D. the carry-out is ignored.
- Correct Answer
- a one will be added to the final result.
- 1. Subtract the following hexadecimal numbers.
47 34 FA ?25 ?1C ?2F
Options- A. 22 18 CB
- B. 22 17 CB
- C. 22 19 CB
- D. 22 18 CC Discuss
- 2. Add the following binary numbers.
0010 0110 0011 1011 0011 1100 +0101 0101 +0001 1110 +0001 1111
Options- A. 0111 1011 0100 0001 0101 1011
- B. 0111 1011 0101 1001 0101 1011
- C. 0111 0111 0101 1001 0101 1011
- D. 0111 0111 0100 0001 0101 1011 Discuss
- 3. Perform the following hex subtraction: ACE16 ? 99916 =
Options- A. 23516
- B. 13516
- C. 03516
- D. 33516 Discuss
- 4. Could the sum output of a full-adder be used as a two-bit parity generator?
Options- A. Yes
- B. No Discuss
- 5. Add the following BCD numbers.
0110 0111 1001 0101 1000 1000
Options- A. 0000 1011 0000 1111 0001 0001
- B. 0001 0001 0001 0101 0001 0001
- C. 0000 1011 0000 1111 0001 0111
- D. 0001 0001 0001 0101 0001 0111 Discuss
- 6. If B[7..0] = 10100101, what is the value of B[6..2]?
Options- A. 10100
- B. 01001
- C. 10010
- D. 00101 Discuss
- 7. The BCD addition of 910 and 710 will give initial code groups of 1001 + 0111. Addition of these groups generates a carry to the next higher position. The correct solution to this problem would be to:
Options- A. ignore the lowest order code group because 0000 is a valid code group and prefix the carry with three zeros
- B. add 0110 to both code groups to validate the carry from the lowest order code group
- C. disregard the carry and add 0110 to the lowest order code group
- D. add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros Discuss
- 8. If [A] = 1011 1010, [B] = 0011 0110, and [C] = [A] ? [B], what is [C 4..2] in decimal?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 9. The range of positive numbers when using an eight-bit two's-complement system is:
Options- A. 0 to 64
- B. 0 to 100
- C. 0 to 127
- D. 0 to 256 Discuss
- 10. Determine the two's-complement of each binary number.
00110 00011 11101
Options- A. 11001 11100 00010
- B. 00111 00010 00010
- C. 00110 00011 11101
- D. 11010 11101 00011 Discuss
Digital Arithmetic Operations and Circuits problems
Search Results
Correct Answer: 22 18 CB
Correct Answer: 0111 1011 0101 1001 0101 1011
Correct Answer: 13516
Correct Answer: Yes
Correct Answer: 0001 0001 0001 0101 0001 0111
Correct Answer: 01001
Correct Answer: add 0110 to the lowest order code group because a carry was generated and then prefix the carry with three zeros
Correct Answer: 4
Correct Answer: 0 to 127
Correct Answer: 11010 11101 00011
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