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Digital Electronics
‣
Boolean Algebra and Logic Simplification
Comments
Question
Derive the Boolean expression for the logic circuit shown below:
Options
A.
B.
C.
D.
Correct Answer
Boolean Algebra and Logic Simplification problems
Search Results
1. Which of the examples below expresses the distributive law of Boolean algebra?
Options
A. (
A
+
B
) +
C
=
A
+ (
B
+
C
)
B.
A
(
B
+
C
) =
AB
+
AC
C.
A
+ (
B
+
C
) =
AB
+
AC
D.
A
(
BC
) = (
AB
) +
C
Show Answer
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Discuss
Correct Answer:
A
(
B
+
C
) =
AB
+
AC
2. Applying DeMorgan's theorem to the expression
, we get ________.
Options
A.
B.
C.
D.
Show Answer
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Discuss
Correct Answer:
3. What is the primary motivation for using Boolean algebra to simplify logic expressions?
Options
A. It may make it easier to understand the overall function of the circuit.
B. It may reduce the number of gates.
C. It may reduce the number of inputs required.
D. all of the above
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Correct Answer: all of the above
4. When grouping cells within a K-map, the cells must be combined in groups of ________.
Options
A. 2s
B. 1, 2, 4, 8, etc.
C. 4s
D. 3s
Show Answer
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Correct Answer: 1, 2, 4, 8, etc.
5. Which of the following expressions is in the sum-of-products (SOP) form?
Options
A. (
A
+
B
)(
C
+
D
)
B. (
A
)
B
(
CD
)
C.
AB
(
CD
)
D.
AB
+
CD
Show Answer
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Discuss
Correct Answer:
AB
+
CD
6. Which is the correct logic function for this PAL diagram?
Options
A.
B.
C.
D.
Show Answer
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Discuss
Correct Answer:
7. Which statement below best describes a Karnaugh map?
Options
A. A Karnaugh map can be used to replace Boolean rules.
B. The Karnaugh map eliminates the need for using NAND and NOR gates.
C. Variable complements can be eliminated by using Karnaugh maps.
D. Karnaugh maps provide a cookbook approach to simplifying Boolean expressions.
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Correct Answer: Karnaugh maps provide a cookbook approach to simplifying Boolean expressions.
8. Which of the examples below expresses the commutative law of multiplication?
Options
A.
A
+
B
=
B
+
A
B.
AB
=
B
+
A
C.
AB
=
BA
D.
AB
=
A
×
B
Show Answer
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Discuss
Correct Answer:
AB
=
BA
9. Applying DeMorgan's theorem to the expression
, we get ________.
Options
A.
B.
C.
D.
Show Answer
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Discuss
Correct Answer:
10. When
are the inputs to a NAND gate, according to De Morgan's theorem, the output expression could be:
Options
A.
X
=
A
+
B
B.
C.
X
= (
A
)(
B
)
D.
Show Answer
Scratch Pad
Discuss
Correct Answer:
X
=
A
+
B
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