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- Question
Since diodes are destroyed by excessive current, circuits must have:
Options- A. higher voltage sources
- B. current limiting resistors
- C. more dopants
- D. higher current sources
- Correct Answer
- current limiting resistors
- 1. What is the peak output voltage for this half-wave rectifier?
Options- A. 1 V
- B. 7.8 V
- C. 10.9 V
- D. 15.6 V Discuss
- 2. DC power should be connected to forward bias a diode as follows:
Options- A. ? anode, + cathode
- B. ? cathode, ? anode
- C. + anode, ? cathode
- D. + cathode, + anode Discuss
- 3. When a diode is forward biased, the voltage across it
Options- A. is directly proportional to the current
- B. is inversely proportional to the current
- C. is directly proportional to the source voltage
- D. remains approximately the same Discuss
- 4. A pn junction allows current flow when
Options- A. the p-type material is more positive than the n-type material
- B. the n-type material is more positive than the p-type material
- C. both the n-type and p-type materials have the same potential
- D. there is no potential on the n-type or p-type materials Discuss
- 5. In a diode schematic, the anode is represented by a(n):
Options- A. triangle
- B. vertical line
- C. zig-zag line
- D. element indicator Discuss
- 6. In a power supply diagram, which block indicates a smooth dc output?
Options- A. transformer
- B. filter
- C. rectifier
- D. regulator Discuss
- 7. The dc current through each diode in a bridge rectifier equals:
Options- A. the load current
- B. half the dc load current
- C. twice the dc load current
- D. one-fourth the dc load current Discuss
- 8. At any given time in an intrinsic piece of semiconductor material at room temperature
Options- A. electrons drift randomly
- B. recombination occurs
- C. holes are created
- D. All of the above Discuss
- 9. Why is heat produced in a diode?
Options- A. due to current passing through the diode
- B. due to voltage across the diode
- C. due to the power rating of the diode
- D. due to the PN junction of the diode Discuss
- 10. If a 169.7 V half-wave peak has an average voltage of 54 V, what is the average of two full-wave peaks?
Options- A. 119.9 V
- B. 108.0 V
- C. 115.7 V
- D. 339.4 V Discuss
Diodes and Applications problems
Search Results
Correct Answer: 7.8 V
Correct Answer: + anode, ? cathode
Correct Answer: remains approximately the same
Correct Answer: the p-type material is more positive than the n-type material
Correct Answer: triangle
Correct Answer: regulator
Correct Answer: the load current
Correct Answer: All of the above
Correct Answer: due to current passing through the diode
Correct Answer: 108.0 V
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