In a series?parallel circuit, individual component power dissipations are calcul

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Question
In a series?parallel circuit, individual component power dissipations are calculated using:
Options
A. individual component parameters
B. a percent of the voltage division ratio squared
C. total current squared multiplied by the resistor values
D. a percent of the total power depending on resistor ratios

Correct Answer

individual component parameters

Series-Parallel Circuits problems

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1. When placed into a circuit, how are electronic components usually connected?
Options
A. positive terminal to positive terminal
B. in parallel
C. as a combination of series and parallel
D. in series

2.

Which circuit fault do the meter readings in the given figure indicate?
Options
A. The 1 kΩ resistor is shorted.
B. The 4.7 kΩ resistor is shorted.
C. The 2.2 kΩ resistor is shorted.
D. The 3.3 kΩ resistor is shorted.

7. What is the power dissipated by R1, R2, and R3?
Options
A. P1 = 0.13 W, P2 = 0.26 W, P3 = 0.12 W
B. P1 = 0.26 W, P2 = 0.52 W, P3 = 0.23 W
C. P1 = 0.52 W, P2 = 0.92 W, P3 = 0.46 W
D. P1 = 1.04 W, P2 = 1.84 W, P3 = 0.92 W

8.

In the given circuit, what is R_UNK equal to if R_V must be adjusted to 1,232 Ω in order to balance the bridge?
Options
A. 220 Ω
B. 6,899 Ω
C. 1,232 Ω
D. More information is needed in order to find R_UNK.

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