Difficulty: Medium
Correct Answer: rp = ksa(Csb-Cs)
Explanation:
Introduction:
When the Damköhler number is very large (NDa ≫ 1), intrinsic enzyme kinetics are so rapid that the surface concentration of substrate adjusts to match the mass transfer supply. In this regime, the bottleneck is the hydrodynamic transport of substrate from the bulk liquid to the enzyme surface, so the measurable overall rate mirrors the flux across the liquid film rather than the enzyme's intrinsic kinetics.
Given Data / Assumptions:
Concept / Approach:
Under mass transfer control, overall uptake equals the film flux. The classic film theory gives flux J = k_s (C_sb − C_s). Multiplying by specific area a yields the volumetric rate r_p = k_s a (C_sb − C_s). Any expression that omits the driving force (C_sb − C_s) or replaces it with sums/products does not represent a diffusion-controlled flux.
Step-by-Step Solution:
Step 1: Recognize the control regime: transport from bulk to surface limits.Step 2: Write the film-flux relation: J = k_s (C_sb − C_s).Step 3: Convert to volumetric rate by multiplying by a: r_p = k_s a (C_sb − C_s).Step 4: Confirm dimensions: k_s [m/s], a [m^2/m^3], concentration difference [mol/m^3] ⇒ r_p [mol/(m^3·s)].
Verification / Alternative check:
Experimental signatures include rate increases with agitation (higher k_s) or reduced particle size (higher a), supporting the mass transfer form and independence from intrinsic V_max in this regime.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming intrinsic kinetic parameters (K_m, V_max) matter under NDa ≫ 1; in this limit, changes in agitation or particle size give the strongest rate response.
Final Answer:
rp = ksa(Csb-Cs)
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