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Home ‣ Java Programming ‣ Exceptions See What Others Are Saying!
  • Question

  • What will be the output of the program? 
    class Exc0 extends Exception { } 
class Exc1 extends Exc0 { } /* Line 2 */
public class Test 
{  
    public static void main(String args[]) 
    { 
        try 
        {  
            throw new Exc1(); /* Line 9 */
        } 
        catch (Exc0 e0) /* Line 11 */
        {
            System.out.println("Ex0 caught"); 
        } 
        catch (Exception e) 
        {
            System.out.println("exception caught");  
        } 
    } 
}


  • Options
  • A. Ex0 caught
  • B. exception caught
  • C. Compilation fails because of an error at line 2.
  • D. Compilation fails because of an error at line 9.

  • Correct Answer
  • Ex0 caught 

    Explanation
    An exception Exc1 is thrown and is caught by the catch statement on line 11. The code is executed in this block. There is no finally block of code to execute.

    More questions

    • 1. What will be the output of the program (in jdk1.6 or above)? 
      public class BoolTest 
{
    public static void main(String [] args) 
    {
        Boolean b1 = new Boolean("false");
        boolean b2;
        b2 = b1.booleanValue();
        if (!b2) 
        {
            b2 = true;
            System.out.print("x ");
        }
        if (b1 & b2) /* Line 13 */
        {
            System.out.print("y ");
        }
        System.out.println("z");
    }
}

    • Options
    • A. z
    • B. x z

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